Question

我尝试在没有GPIO的机器上开发一些代码。作为GPIO库，我选择了gpiozero来编写代码，而无需访问raspberry pi的gpio。我的问题，我无法在代码中使用.when_pressed事件。我模拟了按钮的状态更改，但未调用该函数。

Device.pin_factory = MockFactory()

def interrupt_Event(channel):
   print("%s puted in the queue", channel)

InputPin.Device.pin_factory.pin(channel)
InputPin.when_pressed  = interrupt_Event

def main():
   try:
        while True:

            time.sleep(1)
                    InputPins[channel].pull=drive_high()
                    time.sleep(0.1) 
                    print("State CHANNEL %s" % channel)
                    print(InputPins[channel].state)
                    InputPins[channel].drive_low()

到目前为止，我不知道出什么问题了。

Answer 1

when_pressed函数不应包含参数（请参见https://gpiozero.readthedocs.io/en/stable/recipes.html中的2.7）。

您可以使用循环定义回调：Creating functions in a loop （使用channel = channel强制提前绑定通道值，如下例所示）

for channel in channels:
    def onpress(channel=channel):
        print("%s puted in the queue", channel)
    InputPins[channel].when_pressed = onpress

Answer 2

我不认为您使用drive_high和drive_low模拟按钮按下。我有一个几乎相同的问题。使用Mock引脚在Windows上开发Pi程序，我发现未调用回调例程。

from gpiozero.pins.mock import MockFactory
from gpiozero import Device, Button, LED
from time import sleep

Device.pin_factory = MockFactory()  # set default pin 
factory

btn = Button(16)

# Get a reference to mock pin 16 (used by the button)
btn_pin = Device.pin_factory.pin(16)

def pressed():       #  callback 
    print('pressed')

def released():       #  callback 
    print('released')    

btn.when_pressed  = pressed  
btn.when_released = released  # callback routine

for i in range(3):           # now try to signal sensor
    print('pushing the button')
    btn_pin.drive_high
    sleep(0.1)
    btn_pin.drive_low
    sleep(0.2)

输出没有回调，只有

pushing the button

pushing the button

pushing the button
>>>

模拟gpiozero中的“按下按钮”事件

2 个答案: