Question

在“摘要”（即最后一个if语句）的瀑布对话框的末尾，我想自动进行发布请求，而无需在Postman中进行API调用，eventListener是这样吗？如何包含它？

async summaryStep(step) {
            if (step.result) {
                // Get the current profile object from user state.
                const userProfile = await this.userProfile.get(step.context, new UserProfile());
                userProfile.name = step.values.name;
                //the same for other step values(email, doctor, date)
                let msg = `you want a date with dr. ${userProfile.doctor} , and your name is ${userProfile.name}.`;
                if (userProfile.date !== -1) {
                    msg += `you have an appointment the:  ${userProfile.date}.`;
                }
                await step.context.sendActivity(msg);
                let msg1 = `"${userProfile.date}"`;
                if (msg1) {
                    let z = JSON.stringify(userProfile.name);
                    //and also the other rows to go in the database(email, doctor, date)
                    var name = JSON.parse(z);
                    //and also the other rows to go in the database(email, doctor, date)
                    //this actually works but only if i use postman 
                    var urlencoded = bodyparser.urlencoded({ extended: false });
                    app.post('/id', urlencoded, (req, res) => {
                        app.use(express.json());
                        app.use(express.urlencoded({ extended: true }));
                        mysqlConnection.query("INSERT INTO users(name, email, doctor, date) VALUES('" + userProfile.name + "','" + userProfile.password + "','" + userProfile.doctor + "','" + userProfile.date + "')", function (err, result, rows) {
                            if (err) throw err;
                            console.log("Yeah! record inserted");
                            console.log(name);
                            res.send(result);
                        });
                    });
                    const port = process.env.PORT || 8080;
                    app.listen(port, () => console.log(`Listening on port ${port}..`));
                }

            } else {
                await step.context.sendActivity('Thanks. Your profile will not be kept. Push enter to return Menu');
            }
            return await step.prompt(CONFIRM_PROMPT3, `is that true? ${step.result}`, ['yes', 'no']);
// this if statement should "fire" the post request...
            if (step.result == 'yes') {
                return await step.context.sendActivity(`we will contact you soon ${userProfile.password}.`);
            }
            return await step.endDialog();
        }

Answer 1

根据我的理解，您想知道如何从Azure机器人异步功能调用POST API。请尝试使用您的async summaryStep函数中的以下代码，根据您的要求发送发帖请求。

var rp = require('request-promise');

var options = {
  method: 'POST',
  uri: 'http://localhost:8080/id',
  body: {
    fieldCount:0,
    affectedRows:1,
    //your other body content here...
  },
  json: true,
  headers: {
    'content-type': 'application/json'  //you can append other headers here 
  }
};

await rp(options)
    .then(function (body) {
        console.log(body)
    })
    .catch(function (err) {
      console.log(err)
    });
}

希望有帮助。一种 nd如有任何其他担忧或误解，请随时让我知道。

Answer 2

答案是将您的DataBinder.Eval(Container.DataItem, "rent_amount","{0:C0}") API端点移动到您的机器人已在服务器上运行的app.post文件中。只需旋转一个新的“服务器”和“端口”以使端点可用。然后，在您的index.js（在我的示例中为summaryStep）中，使用Axios，请求承诺或您拥有的东西进行API调用以发布数据。按下API后，数据将被传入并处理。

在下面的代码中，当API被命中时，传入的数据将用于发回机器人的axiosStep中。在您的情况下，您传入的数据将用于数据库调用，您可以在其中使用返回的响应sendActivity。

您的代码如下所示。请注意，为示例起见，sendActivity操作已简化。您将需要更新post操作以进行mySql查询。此示例还利用了服务器的Restify（Bot Framework bot的标准），并使用了与bot相同的端口，但这可以轻松更新为使用Express和/或其他端口。

希望有帮助！

index.js

post

mainDialog.js

[...]

const conversationReferences = {};
const bodyParser = require('body-parser');

server.post('/id', async (req, res) => {
  const { conversationID, data, name } = req.body;
  const conversationReference = conversationReferences[ conversationID ];

  await adapter.continueConversation(conversationReference, async turnContext => {
    var reply = `${ data }. Thanks, ${ name }`;

    await turnContext.sendActivity(reply);
  });
  res.writeHead(200);
  res.end();
});

如何在异步功能内发出发布请求？

2 个答案: