如何将变量从ajax url参数传递到laravel路由?

时间:2019-10-08 11:35:14

标签: javascript ajax laravel

我想像这样将发件人ID传递给laravel路由,但似乎我的代码无法正常工作。请指定正确的方法。

url:'/ agent_close / {sender_id}',


function  closeChat(){
  sender = document.getElementById("sender_id").value;
  $.ajax({
           type: "POST",
           url: '/agent_close/{sender_id}',
           data: "sender_id=" + sender, 
           success: function (data) {
                console.log('Message Closed');
                console.log(data);
            },
            error: function (data) {
                console.log('An error occurred');
                console.log(data);
            },
         });
}

路线为:

Route::post('/agent_close/{sender_id}', 'AgentController@closeAgentThread');

功能:

   public function closeAgentThread($sender_id){
        $bot = new BotManController();
        return $bot->TakeThreadControl($sender_id);
    }

2 个答案:

答案 0 :(得分:2)

url: '/agent_close/' + sender,

答案 1 :(得分:0)

  sender = document.getElementById("sender_id").value;
  $.ajax({
           type: "POST",  //you can use GET instead of POST
           url: '/agent_close/'+sender,   //this line used Route_URL instead Route_name
           data: "",   //can be null
           success: function (data) {
                console.log('Message Closed');
                console.log(data);
            },
            error: function (data) {
                console.log('An error occurred');
                console.log(data);
            },
         });
}