Question

我具有以下功能，可以从表Product_Colors中查找具有相同颜色的产品，并且效果很好：

$colors = ProductColor::query()->
select('color_id', DB::raw("count(*) as amount"))
    ->groupBy('color_id')
    ->having('amount','>=', '3')
    ->get();

我有很多对很多关系：

public function colors() {
   return $this->belongsToMany('App\Color','product_colors');
}

现在我要获得具有相同3种颜色的每种产品。我有这个查询：

$products = Product::whereHas('colors', function(Builder $query) { $query
    ->groupBy('color_id', 'product_id');},'>', '3')->get();

，我什么也没得到，但是我确定我有两种具有3种相同颜色的产品。有人可以帮我提示我做错了什么吗？

我有以下代码来获取所有具有3种以上颜色的项目：

        $products = Product::has('colors', '>', 3)->with('colors')->get();

但是我需要所有超过3种颜色且颜色完全相同的颜色例如：

    "products": [
    {
        "id": 2,
        "title": "net",
        "created_at": "2019-10-08 07:36:42",
        "updated_at": "2019-10-08 07:36:42",
        "colors": [
            {
                "id": 16,
                "name": "Peru",
                "created_at": "2019-10-08 07:36:42",
                "updated_at": "2019-10-08 07:36:42",
                "pivot": {
                    "product_id": 2,
                    "color_id": 16
                }
            },
            {
                "id": 17,
                "name": "Red",
                "created_at": "2019-10-08 07:36:42",
                "updated_at": "2019-10-08 07:36:42",
                "pivot": {
                    "product_id": 2,
                    "color_id": 17
                }
            },
            {
                "id": 20,
                "name": "DarkTurquoise",
                "created_at": "2019-10-08 07:36:42",
                "updated_at": "2019-10-08 07:36:42",
                "pivot": {
                    "product_id": 2,
                    "color_id": 20
                }
            },
            {
                "id": 2,
                "name": "MediumPurple",
                "created_at": "2019-10-08 07:36:42",
                "updated_at": "2019-10-08 07:36:42",
                "pivot": {
                    "product_id": 2,
                    "color_id": 2
                }
            }
        ]
    },
    {
        "id": 3,
        "title": "org",
        "created_at": "2019-10-08 07:36:42",
        "updated_at": "2019-10-08 07:36:42",
        "colors": [
            {
                "id": 2,
                "name": "MediumPurple",
                "created_at": "2019-10-08 07:36:42",
                "updated_at": "2019-10-08 07:36:42",
                "pivot": {
                    "product_id": 3,
                    "color_id": 2
                }
            },
            {
                "id": 16,
                "name": "Peru",
                "created_at": "2019-10-08 07:36:42",
                "updated_at": "2019-10-08 07:36:42",
                "pivot": {
                    "product_id": 3,
                    "color_id": 16
                }
            },
            {
                "id": 17,
                "name": "Red",
                "created_at": "2019-10-08 07:36:42",
                "updated_at": "2019-10-08 07:36:42",
                "pivot": {
                    "product_id": 3,
                    "color_id": 17
                }
            },
            {
                "id": 20,
                "name": "DarkTurquoise",
                "created_at": "2019-10-08 07:36:42",
                "updated_at": "2019-10-08 07:36:42",
                "pivot": {
                    "product_id": 3,
                    "color_id": 20
                }
            }
        ]
    },

Answer 1

我认为您不能像这样对where子句提供检查。

因此，请尝试以下操作：

$products = Product::whereHas('colors', function(Builder $query) 
    { 
        $query->groupBy('color_id', 'product_id')
              ->havingRaw('count(color_id) > 3');
    })
    ->with('colors') // eager load them
    ->get();

它可能无法正常运行，因为我无法尝试，但我希望它至少可以使您了解如何执行此操作。

否则，请在collection实例上使用过滤器。

所以可能是这样的：

$products = Product::has('colors')->with('colors') 
    ->get()
    ->filter(function($item) {
        return $item->colors->count() >= 3;
    });

我不明白Laravel中的工作原理（Builder $ query）

1 个答案: