Question

我正在尝试将数组中包含多个对象的数组弄平。它一直将其展平为一个阵列。我希望它在数组中具有多个对象，但也希望所有内容都扁平化，除去键和值之外的所有内容。

这是当前名为“ livedata”的数组。

    [
       {
           "earningsFileId": {
               "value": 1234
           },
           "paymentType": {
               "value": "Session",
               "errors": [
                   {
                       "id": 802462,
                       "message": "Invalid Combination",
                       "status": "Processing"
                   }
               ]
           },
           "detailStatus": {
               "value": "Processing"
           }
       },
       {
           "earningsFileId": {
               "value": 5678
           },
           "paymentType": {
               "value": "Session",
               "errors": [
                   {
                       "id": 802462,
                       "message": "Invalid Combination",
                       "status": "Processing"
                   }
               ]
           },
           "detailStatus": {
               "value": "Processing"
           }
       }
]

这是我要实现的输出。

[
   {
       "earningsFileId": 1234,
       "paymentType": "Session",
       "detailStatus": "Processing"
   },
   {
        "earningsFileId": 1234,
        "paymentType": "Session",
        "detailStatus": "Processing"
    }
]


data = [];
   Object.values(livedata).map((value, keys) => {
     Object.keys(value).forEach((key) => {
       data[key] = livedata[keys][key]['value']
     })
   });

Answer 1

您需要根据livedata中的每个对象创建一个新的“扁平化”对象。您可以使用Object.entries和reduce将每个键值对获取所需对象的数组：

const livedata = [{
    "earningsFileId": {
      "value": 1234
    },
    "paymentType": {
      "value": "Session",
      "errors": [{
        "id": 802462,
        "message": "Invalid Combination",
        "status": "Processing"
      }]
    },
    "detailStatus": {
      "value": "Processing"
    }
  },
  {
    "earningsFileId": {
      "value": 5678
    },
    "paymentType": {
      "value": "Session",
      "errors": [{
        "id": 802462,
        "message": "Invalid Combination",
        "status": "Processing"
      }]
    },
    "detailStatus": {
      "value": "Processing"
    }
  }
];

const result = livedata.map(d =>
  Object.entries(d).reduce((acc, [k, v]) => {
    acc[k] = v.value;
    return acc;
  }, {}))
console.log(result);

展平对象并将多个对象推入数组

1 个答案: