Question

我做了一个简单的表格：

<%= form_for @recipe do |f| %>
    <%= f.text_field :title, name: 'Título' %>
    <%= f.text_field :recipe_type, name: 'Tipo da Receita' %>
    <%= f.text_field :cuisine, name: 'Cozinha' %>
    <%= f.text_field :difficulty, name: 'Dificuldade' %>
    <%= f.text_field :cook_time, name: 'Tempo de Preparo' %>
    <%= f.text_area :ingredients, name: 'Ingredientes' %>
    <%= f.text_area :cook_method, name: 'Como Preparar' %>
    <%= f.submit :submit, name: 'Enviar %>
<% end %>

但是当我提交它时，出现此错误：

 Failure/Error: params.require(:recipe).permit(:title, :recipe_type, :cuisine, :difficulty, :cook_time, :ingredients, :cook_method)

     ActionController::ParameterMissing:
       param is missing or the value is empty: recipe
     # ./app/controllers/recipes_controller.rb:23:in `recipe_params'
     # ./app/controllers/recipes_controller.rb:16:in `create'
     # ./spec/features/user_register_recipe_spec.rb:18:in `block (2 levels) in <top (required)>'

问题出在提交按钮上，我需要将其命名为Enviar，但是我尝试了所有可能的组合，但没有任何效果。我尝试过：

<%= f.button :submit %>      Unable to find link or button "Enviar"
<%= f.submit 'Enviar' %>     I get the error of missing params
<%= f.submit :submit, name: 'Enviar' %> Unable to find link or button "Enviar"

我不知道该怎么办了。这是我的控制器：

class RecipesController < ApplicationController

  def index
    @recipes = Recipe.all
  end

  def show
    @recipe = Recipe.find(params[:id])
  end

  def new
    @recipe = Recipe.new
  end

  def create
    @recipe = Recipe.new(recipe_params)
    if @recipe.save
      redirect_to recipe_path(@recipe)
    else 
      render :new
    end
  end

  private
    def recipe_params
      params.require(:recipe).permit(:title, :recipe_type, :cuisine, :difficulty, :cook_time, :ingredients, :cook_method)
    end

end

我的路由器：

Rails.application.routes.draw do
  root to: 'recipes#index'
  get 'recipes/new' => 'recipes#new', as: 'new_recipe'
  post 'recipes/new' => 'recipes#create'
  resources :recipes
end

编辑：（在找不到按钮时出错）

$ rspec spec

User register recipe
  successfully (FAILED - 1)

Visitor view recipe details
  successfully
  and return to recipe list

Visitor visit homepage
  successfully
  and view recipe
  and view recipes list

Failures:

  1) User register recipe successfully
     Failure/Error: click_on 'Enviar'

     Capybara::ElementNotFound:
       Unable to find link or button "Enviar"
     # ./spec/features/user_register_recipe_spec.rb:18:in `block (2 levels) in <top (required)>'

Finished in 0.8137 seconds (files took 11.14 seconds to load)
6 examples, 1 failure

Failed examples:

rspec ./spec/features/user_register_recipe_spec.rb:4 # User register recipe successfully

缺少mapam：recipe时出错

rspec spec

User register recipe
  successfully (FAILED - 1)

Visitor view recipe details
  successfully
  and return to recipe list

Visitor visit homepage
  successfully
  and view recipe
  and view recipes list

Failures:

  1) User register recipe successfully
     Failure/Error: click_on 'Enviar uma receita'

     SyntaxError:
       /home/italo/Área de Trabalho/code-saga/3/cookbook_parte4/app/views/recipes/new.html.erb:11: syntax error, unexpected tLABEL, expecting '='
       ...buffer.append=( f.submit, name:'Enviar' );@output_buffer.saf...
       ...                          ^~~~~
     # ./spec/features/user_register_recipe_spec.rb:9:in `block (2 levels) in <top (required)>'

Finished in 0.35119 seconds (files took 1.09 seconds to load)
6 examples, 1 failure

Failed examples:

rspec ./spec/features/user_register_recipe_spec.rb:4 # User register recipe successfully

Answer 1

您将覆盖所有表单字段上的name属性，这将导致空的食谱参数哈希。我以为这是错误的，这些都是标签。

从表单字段中删除所有name:，并改用标签。即...

<%= f.label :title, "Título" %>
<%= f.text_field :title %>

对于按钮，请使用<%= f.submit 'Enviar' %>

阅读Form Helpers

<％= f.submit％>不会将参数发送到Controller。（Ruby On Rails）

1 个答案: