Question

我正在尝试将卡发给两只手（每只手都放在一张列表中）。双手握在第二张表中。但是，玩家1的纸牌与玩家2的纸牌完全相同，就好像我的外部列表中有重复列表一样。这是因为可变性吗？

代码片段应有助于解释。救命！我在做什么错了，我该如何解决？

代码

no_of_cards_each = 3
no_of_players = 2
cards = ["AH", "2H", "3H", "4H", "5H", "6H", "7H"]
player_hands = []

for _ in range(no_of_players):
    player_hands.append([])

print(f"Empty hands = {player_hands}")

for card_num in range(no_of_cards_each):
    print(f"Card Num is {card_num}")
    for player_num in range(no_of_players):
        print(f"Player number is {player_num}")
        next_card = cards.pop(0)
        player_hands[player_num].append(next_card)
        print(f"Player number {player_num} got dealt a {next_card}")

print(f"The final hands look like {player_hands}")

输出

Empty hands = [[], []]
Card Num is 0
Player number is 0
Player number 0 got dealt a AH
Player number is 1
Player number 1 got dealt a 2H
Card Num is 1
Player number is 0
Player number 0 got dealt a 3H
Player number is 1
Player number 1 got dealt a 4H
Card Num is 2
Player number is 0
Player number 0 got dealt a 5H
Player number is 1
Player number 1 got dealt a 6H

最后一手牌看起来像[['AH', '3H', '5H'], ['2H', '4H', '6H']]。

进程退出代码为0。

Answer 1

玩家1是否没有['AH'，'3H'，'5H']，而玩家2是否具有['2H'，'4H'，'6H']？你的卡是什么意思

Answer 2

哇！抱歉。经过几天的努力，当我重新格式化代码以将问题粘贴到这里时，它开始按预期工作。我想有时候代码刚开始起作用的时候就已经放弃了。我应该在发布前最后一次查看结果。抱歉浪费您的时间。

我应该撤回该问题（如果可能）还是将其留在这里？如果没有其他问题，对于其他遇到2D列表问题的人来说，这可能是一个有用的代码段：）

不明白为什么2D列表元素被赋予相同的值

2 个答案: