Question

我无法将文本文件中的矩阵存储到2D数组中。每次我运行以下代码时，它都不会错误执行，但是控制台中不会打印任何内容。任何帮助将不胜感激。我的代码如下所示：


public static void main(String[] args) throws FileNotFoundException {

        Scanner sc = new Scanner(new File("input1.txt"));
        String [][] array = new String [9][9];

        try{

            for(int i = 0; i > array.length; i++) {
                for(int j = 0; j < array[0].length; j++) {
                    array[i][j] = sc.next();
                    System.out.print(array[i][j] + " ");
                }

            }

        }catch(Exception e){
            System.out.print("error");

        }

这也是我正在阅读的文本文件的内容：

5 3 4 6 7 8 9 1 2
6 7 2 1 9 5 3 4 8
1 9 8 3 4 2 5 6 7
8 5 9 7 6 1 4 2 3
4 2 6 8 5 3 7 9 1
7 1 3 9 2 4 8 5 6
9 6 1 5 3 7 2 8 4
3 4 5 2 8 6 1 7 9

Answer 1

问题出在您的第一个循环上，而且当nextInt()的内容为"input1.txt"时最好使用int

public static void main(String[] args) throws FileNotFoundException {

        Scanner sc = new Scanner(new File("input1.txt"));
        int [][] array = new int [9][9];

        try{

            for(int i = 0; i < array.length; i++) {
                for(int j = 0; j < array[0].length; j++) {
                    array[i][j] = sc.nextInt();
                    System.out.print(array[i][j] + " ");
                }

            }

        }catch(Exception e){
            System.out.print("error");

        }

Answer 2

您首先在for循环中出错

    Scanner sc = new Scanner(new File("input1.txt"));
    String [][] array = new String [9][9];

    try{

        for(int i = 0; i < array.length; i++) { // your error was here. you wrote int i = 0 i > array.length; i++
            for(int j = 0; j < array[0].length; j++) {
                array[i][j] = sc.next();
                System.out.print(array[i][j] + " ");
            }

        }

    }catch(Exception e){
        System.out.print("error");

    }

将文本文件中的矩阵存储到2D数组中

2 个答案: