Question

我有一个函数，它接受用户输入以告诉它要输出多少个随机数，以及要在其之间进行随机数运算的范围（例如1-90）。问题在于它将给出重复的数字，但是我只需要唯一的数字。有谁知道我该如何更改代码来实现这一目标？

function random() {
    let randomNums = [];

// Get how many random numbers to output
    let numBox = document.querySelector('.numBox').value;

// Get the highest number range should go to (ex. 1-70)
    let highestNumber = document.querySelector('.highestNumber').value;

// Loop to generate random numbers and push to randomNums array
    for (let i = 0; i < numBox; i++) {
        let num = Math.floor(Math.random() * highestNumber) + 1;
        randomNums.push(` ${num}`)  
    }     

// Sort numbers from lowest to highest
    randomNums.sort(function(a, b) {return a - b;});

// Output numbers
    document.querySelector('.randomOutput').innerHTML = randomNums;
}

Answer 1

只需将您的循环更改为while循环，然后检查数组是否尚未具有该值：

let i = 0;
while(i < numBox) {
    let num = Math.floor(Math.random() * highestNumber) + 1;
    if (randomNums.indexOf(num) == -1) {
        randomNums.push(num);
        i++;
    }
}

Answer 2

您可以简单地生成并验证它是否存在，直到获得必要的随机唯一编号为止

while (randomNums.length < numBox) {
    let num = Math.floor(Math.random() * highestNumber) + 1;
    if (randomNums.indexOf(num) === -1) randomNums.push(num);
}

Answer 3

这是一种避免while()循环的方法。

使用从1到最大值的数字填充数组
随机化数组（我从this answer借来了Fisher-Yates算法）
从数组中选择前N个项目

function random() {
  let randomNums = [];

  // Get how many random numbers to output
  let numBox = document.querySelector('.numBox').value;

  // Get the highest number range should go to (ex. 1-70)
  let highestNumber = document.querySelector('.highestNumber').value;

  // Loop to generate random numbers and push to randomNums array
  for (let i = 1; i <= highestNumber; i++) {
    randomNums.push(i)
  }

  randomNums = shuffle(randomNums).slice(0, numBox);

  // Sort numbers from lowest to highest
  randomNums.sort(function(a, b) {
    return a - b;
  });

  // Output numbers
  document.querySelector('.randomOutput').innerHTML = randomNums;
}

function shuffle(a) {
  var j, x, i;
  for (i = a.length - 1; i > 0; i--) {
    j = Math.floor(Math.random() * (i + 1));
    x = a[i];
    a[i] = a[j];
    a[j] = x;
  }
  return a;
}

random();

<input class="numBox" value="4"> out of <input class="highestNumber" value="48">
<div class="randomOutput"></div>
<button onclick="random()">randomize</button>

Answer 4

如果其他人有类似的问题，这是修复它的代码：

function random() {
    let randomNums = [];
    let included = {};
    let numBox = document.querySelector('.numBox').value;
    let highestNumber = document.querySelector('.highestNumber').value;

    for (let i =0; i<numBox; i++) {
        let temp = true;
        while(temp) {
            let num = Math.floor(Math.random() * highestNumber) + 1;
            if (included[num] === undefined) {
                temp = false
                randomNums.push(` ${num}`)
                included[num] = num
               }
        }
    }
    randomNums.sort(function(a, b) {return a - b;});
    document.querySelector('.randomOutput').innerHTML = randomNums;
}

Answer 5

如@CodeManiac所述

，在@BilalSiddiqui解决方案中使用“设置”。

solve_ivp

如何获得一定范围内的一定数量的唯一随机数？

5 个答案: