Question

鉴于以下表格：

学生

+----+-------+
| id | Name  |
+----+-------+
| 1  | Chris |
| 2  | Joe   |
| 3  | Jack  |
+----+-------+

注册

+---------------+------------+-----------+----------+
| enrollment_id | student_id | course_id | complete |
+---------------+------------+-----------+----------+
| 1             | 1          | 55        | true     |
| 2             | 1          | 66        | true     |
| 3             | 1          | 77        | true     |
| 4             | 2          | 55        | true     |
| 5             | 2          | 66        | false    |
| 6             | 3          | 55        | false    |
| 7             | 3          | 66        | true     |
+---------------+------------+-----------+----------+

我想要以下

+----+-------+-----------+-----------+-----------+
| id | Name  | Course 55 | Course 66 | Course 77 |
+----+-------+-----------+-----------+-----------+
| 1  | Chris | true      | true      | true      |
| 2  | Joe   | true      | false     | NULL      |
| 3  | Jack  | false     | true      | NULL      |
+----+-------+-----------+-----------+-----------+

注意1：我知道mysql不能有动态列（如果我错了，请纠正我！）所以我很满意查询的开头：

SELECT id, name, course_55, course_66, course_77 etc...

我对此很满意，因为有一定数量的课程（准确地说是4个）。理想我希望它是动态的;也就是说，不必手动编写SELECT子句中的每个课程。

注2：这需要mysql纯 - 我不想诉诸PHP。

该数据库目前有10000多名学生，入学人数超过10000 + 4（因为正好有4门课程，每个学生都在4个模块中）。

注3： Student.user_id已编入索引，所以为enrollment.enrollment_id，enrollment.student_id和enrollment.course_id。

Answer 1

select s.id,s.name,
max(case when e.course_id = 55 then complete else null end) as c55,
max(case when e.course_id = 66 then complete else null end) as c66,
max(case when e.course_id = 77 then complete else null end) as c77
from student as s
left join enrollment as e
on s.id = e.student_id
group by s.id

@克里斯。使用存储过程甚至可以在不知道列数之前创建动态数据透视表。这是链接

http://forum.html.it/forum/showthread.php?s=&threadid=1456236

我在意大利论坛上对类似问题的回答。有一个完整的例子可以帮助您理解背后的逻辑。 :)

修改。使用MYSQL DYNAMIC VIEW更新

这是我的首发转储：

/*Table structure for table `student` */

drop table if exists `student`;

create table `student` (
  `id` int(10) unsigned not null auto_increment,
  `name` varchar(50) default null,
  primary key (`id`)
) engine=myisam;

/*Data for the table `student` */

insert  into `student`(`id`,`name`) values (1,'chris');
insert  into `student`(`id`,`name`) values (2,'joe');
insert  into `student`(`id`,`name`) values (3,'jack');

drop table if exists enrollment;

create table `enrollment` (
  `enrollment_id` int(11) auto_increment primary key,
  `student_id` int(11) default null,
  `course_id` int(11) default null,
  `complete` varchar(50) default null
) engine=myisam auto_increment=8 default charset=latin1;

/*Data for the table `enrollment` */

insert  into `enrollment`(`enrollment_id`,`student_id`,`course_id`,`complete`) values (1,1,55,'true');
insert  into `enrollment`(`enrollment_id`,`student_id`,`course_id`,`complete`) values (2,1,66,'true');
insert  into `enrollment`(`enrollment_id`,`student_id`,`course_id`,`complete`) values (3,1,77,'true');
insert  into `enrollment`(`enrollment_id`,`student_id`,`course_id`,`complete`) values (4,2,55,'true');
insert  into `enrollment`(`enrollment_id`,`student_id`,`course_id`,`complete`) values (5,2,66,'false');
insert  into `enrollment`(`enrollment_id`,`student_id`,`course_id`,`complete`) values (6,3,55,'false');
insert  into `enrollment`(`enrollment_id`,`student_id`,`course_id`,`complete`) values (7,3,66,'true');

这是动态视图的存储过程：

delimiter //
drop procedure if exists dynamic_view//
create procedure dynamic_view()
begin
declare finish int default 0;
declare cid int;
declare str varchar(10000) default "select s.id,s.name,";
declare curs cursor for select course_id from enrollment group by course_id;
declare continue handler for not found set finish = 1;
open curs;
my_loop:loop
fetch curs into cid;
if finish = 1 then
leave my_loop;
end if;
set str = concat(str, "max(case when e.course_id = ",cid," then complete else null end) as course_",cid,",");
end loop;
close curs;
set str = substr(str,1,char_length(str)-1);
set @str = concat(str," from student as s
            left join enrollment as e
            on s.id = e.student_id
            group by s.id");
prepare stmt from @str;
execute stmt;
deallocate prepare stmt;
-- select str;
end;//
delimiter ;

现在让我们称之为

mysql> call dynamic_view();
+----+-------+-----------+-----------+-----------+
| id | name  | course_55 | course_66 | course_77 |
+----+-------+-----------+-----------+-----------+
|  1 | chris | true      | true      | true      |
|  2 | joe   | true      | false     | NULL      |
|  3 | jack  | false     | true      | NULL      |
+----+-------+-----------+-----------+-----------+
3 rows in set (0.00 sec)

Query OK, 0 rows affected (0.05 sec)

现在我们插入两个不同课程的其他两个记录：

insert  into `enrollment`(`student_id`,`course_id`,`complete`) values (1,88,'true');
insert  into `enrollment`(`student_id`,`course_id`,`complete`) values (3,99,'true');

我们记得这个程序。这是结果：

mysql> call dynamic_view();
+----+-------+-----------+-----------+-----------+-----------+-----------+
| id | name  | course_55 | course_66 | course_77 | course_88 | course_99 |
+----+-------+-----------+-----------+-----------+-----------+-----------+
|  1 | chris | true      | true      | true      | true      | NULL      |
|  2 | joe   | true      | false     | NULL      | NULL      | NULL      |
|  3 | jack  | false     | true      | NULL      | NULL      | true      |
+----+-------+-----------+-----------+-----------+-----------+-----------+
3 rows in set (0.00 sec)

Query OK, 0 rows affected (0.02 sec)

这就是全部。：）

加入两个表（具有1-M关系），其中第二个表需要“展平”为一行

1 个答案: