将asp mvc3不显眼验证与jquery验证插件混合使用

时间:2011-04-28 23:14:40

标签: jquery asp.net validation asp.net-mvc-3 plugins

对于asp mvc3客户端验证,是否可以将默认的,开箱即用的不引人注目的样式与jquery验证插件混合使用?

这是视图中的表单:

@using (Html.BeginForm("", "", FormMethod.Post, new { id = "newRatingForm" }))
{   
    @Html.ValidationSummary(true)
    <fieldset>
        <legend>Rating</legend>

        <div class="editor-label">
            @Html.LabelFor(model => model.Rate)
        </div>
        <div class="editor-field">
            @Html.EditorFor(model => model.Rate)
            @Html.ValidationMessageFor(model => model.Rate)
        </div>

        <div class="editor-label">
            @Html.LabelFor(model => model.Email)
        </div>
        <div class="editor-field">
            @Html.EditorFor(model => model.Email)
            @Html.ValidationMessageFor(model => model.Email)
        </div>

        <p>
            <input type="submit" value="Create" />
        </p>
    </fieldset>
}

默认情况下,Unobtusive在模型属性上使用通常的验证属性。目标是用[fyneworks] [1] jquery星级评级插件替换表单中的'model.Rate'位,并使用jquery验证插件仅用于表单的那一部分:

<span>Your Rating:</span>
<div id="ratingStars">
    <input class="star {split:2}" type="radio" name="Rating" value="0.5"/>
    <input class="star {split:2}" type="radio" name="Rating" value="1.0"/>
    <input class="star {split:2}" type="radio" name="Rating" value="1.5"/>
    <input class="star {split:2}" type="radio" name="Rating" value="2.0"/>
    <input class="star {split:2}" type="radio" name="Rating" value="2.5"/>
    <input class="star {split:2}" type="radio" name="Rating" value="3.0"/>
    <input class="star {split:2}" type="radio" name="Rating" value="3.5"/>
    <input class="star {split:2}" type="radio" name="Rating" value="4.0"/>
    <input class="star {split:2}" type="radio" name="Rating" value="4.5"/>
    <input class="star {split:2}" type="radio" name="Rating" value="5.0"/>
</div>

我已经劫持了表单的提交操作并将表单值转换为Json以执行ajax请求:

$("#newRatingForm").submit(function (event) {
    event.preventDefault();

    if ($(this).valid()) {        
        newRatingSubmit();
    }    
}); 

function newRatingSubmit() {
    //jquery ajax request using form values converted to Json
}

单选按钮似乎打破了表单,劫持代码不再有效,即当我点击提交时,没有向服务器发出请求(在firebug控制台上观看),表单就消失了。再一次,只用普通的mvc3格式就可以了。

我尝试为评级单选按钮添加jquery验证规则,但似乎没有任何区别:

$("#newRatingForm").validate({
    meta: "validate", 
    errorLabelContainer: "#ErrorDiv",
    wrapper: "div",
    rules:
    {
        Rating: {
            required: true
        }
    },

    messages:
    {
        Rating: {
            required: 'A Rating required.'
        }
    },

    onfocusout: false,
    onkeyup: false,

    //handle validation ok, POST submit
    submitHandler: function (label) {
        newRatingSubmit();
    }
 });

作为替代方案,我可以使用jquery验证插件使用星级评级插件验证标准html表单,并使用上面的代码提交,但这似乎不是'asp.net mvc'。例如,我需要2组验证消息 - 1个用于服务器,使用验证属性,另一个用于客户端视图。

2 个答案:

答案 0 :(得分:2)

jQuery.validator.addMethod("methodeName", function (value, element, params) {
        if (somthing) {
            return false;
        }
        return true;
    });

    jQuery.validator.unobtrusive.adapters.addBool("methodeName");

并在html中添加2个属性

dal-val = true和dal-val-methodeName="errorMessage"

答案 1 :(得分:0)

正如@Vadim所建议的那样,我用data-val =“true”data-val-required =“请输入你的评分”来装饰我的表单的星级评级控件,如下所示;

<div id="ratingStars">
        <input class="star {split:2}" type="radio" name="Rating" value="0.5" data-val="true" data-val-required="Please enter your rating"/>
        <input class="star {split:2}" type="radio" name="Rating" value="1.0" data-val="true"data-val-required="Please enter your rating"/>
        <input class="star {split:2}" type="radio" name="Rating" value="1.5" data-val="true" data-val-required="Please enter your rating"/>
        <input class="star {split:2}" type="radio" name="Rating" value="2.0" data-val="true" data-val-required="Please enter your rating"/>
        <input class="star {split:2}" type="radio" name="Rating" value="2.5" data-val="true" data-val-required="Please enter your rating"/>
        <input class="star {split:2}" type="radio" name="Rating" value="3.0" data-val="true" data-val-required="Please enter your rating"/>
        <input class="star {split:2}" type="radio" name="Rating" value="3.5" data-val="true" data-val-required="Please enter your rating"/>
        <input class="star {split:2}" type="radio" name="Rating" value="4.0" data-val="true" data-val-required="Please enter your rating"/>
        <input class="star {split:2}" type="radio" name="Rating" value="4.5" data-val="true" data-val-required="Please enter your rating"/>
        <input class="star {split:2}" type="radio" name="Rating" value="5.0" data-val="true" data-val-required="Please enter your rating"/>
    </div>
    <span data-valmsg-replace="true" data-valmsg-for="Rating" class="field-validation-valid" style="display:block; width:80px"></span>

我认为我不需要自定义验证器,因为jquery默认的'required'验证器可以正常运行。这种方式有效。但是,我第一次点击提交,我得到了我希望的确切结果;

validation ok with 1st submit

如果我然后选择评级并再次点击提交(不输入电子邮件),表单就会从视图中“消失”而我的控制器没有被点击。

如果我用纯文本框替换单选按钮而不是接受评级;

<input type="text" name="Rating" id="Rating" data-val-required="Please enter your rating" data-val="true" class="text-box single-line"/>

它工作得很好,当我点击提交时我的控制器被点击了。不幸的是,文本框对评级没有好处。