我有一组对象以data
的形式返回给我,我希望创建一组新数据,同时保留旧数据以备将来使用。
我正在尝试遍历给定的数据以创建一组新数据,该数据集不仅包含年龄,而且还删除了所有重复项。我不太确定从哪里开始。
data = [
{
"firstName": "John",
"lastName": "Doe",
"age": "99"
},
{
"firstName": "Jimmy",
"lastName": "Hendricks",
"age": "50"
},
{
"firstName": "William",
"lastName": "Shakespeare",
"age": "22"
},
{
"firstName": "Jane",
"lastName": "Eyre",
"age": "50"
}
]
我最终想得到的是这样的东西:
newData = [
{"age": "99"},
{"age": "50"},
{"age": "22"}
]
答案 0 :(得分:2)
或者您也可以使用Set
来消除重复项:
// ages variable contain just the ages
const ages = data.map(person => person.age);
// new Set(ages) will remove duplicated values:
const newSet = Array.from(new Set(ages)).map(age => ({ age: age }));
答案 1 :(得分:2)
哇,方法太多了! 这是另一个纯粹的功能:
data = [ { "firstName": "John", "lastName": "Doe", "age": "99" }, { "firstName": "Jimmy", "lastName": "Hendricks", "age": "50" }, { "firstName": "William", "lastName": "Shakespeare", "age": "22" }, { "firstName": "Jane", "lastName": "Eyre", "age": "50" } ];
console.log(
Object.keys(data.reduce((obj,o)=>
(obj[o.age]=1,obj),{}))
.map(k=>({age:k}))
)
答案 2 :(得分:1)
let newData = [];
let uniques = [];
data.forEach(el => {
if(!uniques.includes(el.age)){
newData.push({age: el.age});
uniques.push(el.age);
}
});
答案 3 :(得分:1)
const data = [
{
"firstName": "John",
"lastName": "Doe",
"age": "99"
},
{
"firstName": "Jimmy",
"lastName": "Hendricks",
"age": "50"
},
{
"firstName": "William",
"lastName": "Shakespeare",
"age": "22"
},
{
"firstName": "Jane",
"lastName": "Eyre",
"age": "50"
}
]
const newdata = data
.map(({age}) => ({age})) // convert `{age: <value of age>}`
.filter(function({age}) {
const isUnique = !this.has(age); //check if already present
this.add(age); //add anyway
return isUnique; //filter keeping uniques
}, new Set());//use a Set as the `this` context for the filter
console.log(newdata);