Question

这是我的编码：

def main():
global x
PASSWORD_LOG_FILE = "ITWORKS_password_log.txt"
no_of_pw_small = 0
no_of_pw_big = 0
password_log_list = []
input_file = open(PASSWORD_LOG_FILE, "r")
for line in input_file:
    password_log_list.append(line.strip("\n"))
for x in password_log_list:
    print(x)
for line in password_log_list:
    if "password < 6" in line:
        no_of_pw_small = no_of_pw_small + 1
    elif "password > 10" in line:
        no_of_pw_big = no_of_pw_big + 1
        print("The number of small password attempts is", no_of_pw_small)
        print("The number of large password attempts is", no_of_pw_big)
input_file.close()

说您想要什么，我已经知道了。现在，引用的文件有大约30行错误的密码尝试，其特征是过小或过大。此处的目标是计算文件中哪些元素的密码太小而密码太大，然后输出这两个元素的总数。我似乎无法做到。它在通过列表时输出整个方程，而不仅仅是整个方程。任何人都可以理解并解决似乎是我的困境吗？那太好了。谢谢。

Answer 1

将这两行移出for循环：

print("The number of small password attempts is", no_of_pw_small)
print("The number of large password attempts is", no_of_pw_big)

如何在列表中打印变量的最后一个元素？

1 个答案: