我已经增加了文件大小。但是仍然不起作用,我想添加这些代码中的任何一个,并在文件可访问的情况下增加文件的大小...
MySQL 5,PHP 5
$permited = array('jpg', 'jpeg', 'png', 'gif');
$file_name = $_FILES['image']['name'];
$file_size = $_FILES['image']['size'];
$file_temp = $_FILES['image']['tmp_name'];
$div = explode('.', $file_name);
$file_ext = strtolower(end($div));
$unique_image = substr(md5(time()), 0, 10) . '.' . $file_ext;
$uploaded_image = "upload/" . $unique_image;
if ($title == "" || $cat == "" || $body == "" || $tags == "") {
echo "<span class='error'> Must be Fill</span>";
} else {
if (!empty($file_name)) {
if ($file_size > 50048567) {
echo "<span class='error'>Image Size should be less then 1MB!
</span>";
} elseif (in_array($file_ext, $permited) === false) {
echo "<span class='error'>You can upload only:-"
. implode(', ', $permited) . "</span>";
} else {
move_uploaded_file($file_temp, $uploaded_image);
$query = "UPDATE tbl_post
SET
答案 0 :(得分:-1)
您的代码对我来说不错,但是您可以在下面尝试这种方法,以检查上传时是否有错误。
<?php
$target_dir = "uploads/";
$target_file = $target_dir . basename($_FILES["image"]["name"]);
$uploadOk = 1;
$imageFileType = strtolower(pathinfo($target_file, PATHINFO_EXTENSION));
// Check if image file is a actual image or fake image
if (isset($_POST["submit"])) {
$check = getimagesize($_FILES["image"]["tmp_name"]);
if ($check !== false) {
echo "File is an image - " . $check["mime"] . ".";
$uploadOk = 1;
} else {
echo "File is not an image.";
$uploadOk = 0;
}
}
// Check if file already exists
if (file_exists($target_file)) {
echo "Sorry, file already exists.";
$uploadOk = 0;
}
// Check file size
if ($_FILES["image"]["size"] > 500000) {
echo "Sorry, your file is too large.";
$uploadOk = 0;
}
// Allow certain file formats
if ($imageFileType != "jpg" && $imageFileType != "png" && $imageFileType != "jpeg"
&& $imageFileType != "gif") {
echo "Sorry, only JPG, JPEG, PNG & GIF files are allowed.";
$uploadOk = 0;
}
// Check if $uploadOk is set to 0 by an error
if ($uploadOk == 0) {
echo "Sorry, your file was not uploaded.";
// if everything is ok, try to upload file
} else {
if (move_uploaded_file($_FILES["image"]["tmp_name"], $target_file)) {
echo "The file ". basename($_FILES["image"]["name"]). " has been uploaded.";
// do you sql query
} else {
echo "Sorry, there was an error uploading your file.";
}
}