Question

我有两个桌子。与公司同桌。与工作人员的另一张桌子。我想和他们现任官员一起给公司看。

每家公司都有高级职员的历史。公司表格如下：

 -------------------------------
| company_number | name         |
|-------------------------------|
| B1204_GnR103   | Flower LLC   |
| B1204_GnR104   | Marketing LLC|
 -------------------------------

军官表如下：

 -----------------------------------------------
| id | name         | company_id   | start_date |
|-----------------------------------------------|
| 1  | John Doe     | B1204_GnR103 | 2018-02-06 |
| 2  | Dianne Ameter| B1204_GnR104 | 2017-01-07 |
| 3  | Dylan Mering | B1204_GnR103 | 2016-04-23 |
| 4  | Fleece Gold  | B1204_GnR103 | 2019-05-12 |
| 5  | Frank Kern   | B1204_GnR104 | 2019-09-18 |
| 6  | Andreas Frank| B1204_GnR104 | 2017-03-08 |
 -----------------------------------------------

我尝试了一个子选择，但无法使其正常工作。

我尝试了以下语句，但收到错误消息。

SELECT  DISTINCT company.name, 
        officer.name,
        officer.start_date
FROM company
INNER JOIN officer ON company.company_number =  
                        (SELECT officer.name,
                        DATE_FORMAT(officer.start_date, '%Y-%m-%d') AS date
                        FROM officer 
                        WHERE company.company_number = officer.company_id
                        ORDER BY date
                        LIMIT 1)

输出应为以下内容：

Company Name | Officer 
----------------------------
Flower LLC   | Fleece Gold
Marketing LLC| Frank Kern

因为这些人是最晚开始日期的人，并且是公司的现任官员。

但是我收到一条错误消息“操作数应包含1列”。

感谢您的任何建议，谢谢！

Answer 1

您需要将JOIN和company表officer转换为每个公司最大start_date的派生表才能获得所需的结果：

SELECT c.name AS company,
       o.name AS officer,
       o.start_date
FROM company c
JOIN officer o ON o.company_id = c.company_number
JOIN (SELECT company_id, MAX(start_date) AS start_date
      FROM officer
      GROUP BY company_id) m ON m.company_id = o.company_id AND m.start_date = o.start_date

输出：

company         officer         start_date
Flower LLC      Fleece Gold     2019-05-12 00:00:00
Marketing LLC   Frank Kern      2019-09-18 00:00:00

Demo on dbfiddle

MYSQL：仅根据日期返回每个组的最新记录

1 个答案: