Question

我有一个对象数组，想要基于另一个字符串数组的值对其进行过滤，并删除不包含任何字符串的对象。

我尝试对字符串数组使用split并在forEach中搜索每个术语，但是没有用，然后尝试了以下作为过滤器的过滤器，但是它过滤的不是部分完全匹配。

var employees = [
  {"name": "zxc asd", "age":"30"},
  {"name": "asd", "age":"24"},
  {"name": "qwe", "age":"44"},
  {"name": "zxc", "age":"28"},
];

var keepNames = ["asd", "qwe"];

keepNames = keepNames.map(name => {
  return name.toLowerCase();
});


var filteredEmployees = employees.filter(emp => {
  return keepNames.indexOf(emp.name.toLowerCase()) !== -1;
});

console.log( filteredEmployees );

Expected Output[  
  {"name": "zxc asd", "age":"30"},
  {"name": "asd", "age":"24"},
  {"name": "qwe", "age":"44"}];

Actual Output [
  {"name": "asd", "age":"24"},
  {"name": "qwe", "age":"44"}]

非常感谢您的帮助。预先感谢

Answer 1

您还需要迭代名称为keep的数组并检查该值。

var employees = [{ name: "zxc asd", age: "30" }, { name: "asd", age: "24" }, { name: "qwe", age: "44" }, { name: "zxc", age: "28" }],
    keep = ["asd", "qwe"],
    filtered = employees.filter(({ name }) =>
        keep.some(n => name.toLowerCase().includes(n))
    );

console.log(filtered);

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Answer 2

indexOf使用strict equality，因此不会部分匹配。

您可以使用some和includes

var employees = [ {"name": "zxc asd", "age":"30"},{"name": "asd", "age":"24"},{"name": "qwe", "age":"44"},{"name": "zxc", "age":"28"},];
var filterBy = ["asd", "qwe"];

var filteredEmployees = employees.filter(emp => {
  return filterBy.some(v => emp.name.toLowerCase().includes(v.toLowerCase()))
});

console.log(filteredEmployees);

根据字符串数组“具有部分匹配”来过滤对象数组

2 个答案: