我在代码unhashable type: 'list'中遇到此错误
我有一个带有此输入的文本文件：
hokejistov hokej
strelena strela
trener trenuje
我想将单词分为2行。第一行将包含第一个单词。第二行将包含第二个单词。然后，我需要将单词分为符号。这部分工作正常，但是我需要使用字典(mapka = {'h':1,'o':2,'k':3, 'e':4, 'j':5, 'i':6, 's':7, 't':8,'v':9,'r':10, 'l':11, 'n':12, 'a':13, 'u':14})。
在输出中，我想得到这个：
first = [[1, 2, 3, 4, 5, 6, 7, 8, 2, 9], [7, 8, 10, 4, 11, 4, 12, 13], [8, 10, 4, 12, 4, 10]]
second = [[1, 2, 3, 4, 5], [7, 8, 10, 4, 11, 13], [8, 10, 4, 12, 14, 5, 4]]
这是我的代码
data = [line.strip() for line in open("mamradhokej.txt",'r')]
mapka = {'h':1,'o':2,'k':3, 'e':4, 'j':5, 'i':6, 's':7, 't':8,'v':9,
'r':10, 'l':11, 'n':12, 'a':13, 'u':14}
first = [[word.lower() for word in text.split()[0]]for text in data]
second = [[word.lower() for word in text.split()[1]]for text in data]
print(first)
print(second)
map(mapka.get, first)
[mapka[k] for k in first] #here i am getting Type error: unhashable type: 'list'.
答案 0 :(得分：3)
字典键必须是可哈希对象。
为了使对象可哈希化，它应该是实现function sendEmail(event){
var sheet = event.range.getSheet();
if(sheet.getName() !== 'Sheet1') {
// if it's not the correct sheet we end the function here
return;
}
var range = event.range;
var row = range.getRow(); // we get the index of the row of the
edited
cell
var dataRange = sheet.getRange("A" + row + ":C" + row);
var values = dataRange.getValues();
var rowValues = values[0];
var recipient = rowValues[0];
var email = rowValues[1];
var refillsNumber = rowValues[2];
if (refillsNumber = 2) {
// if 'refillsNumber' is not equal to 2 we end the function here
var message = 'Dear ' + recipient + ',\n\n'+ 'You have ' +
refillsNumber + ' remaining would you like to buy more?' + '\n\n' +
'Kind regards,' + '\n\n' + 'The revol team.';
var subject = 'Refill reminder';
MailApp.sendEmail(email,subject,message);
return
}
if (refillsNumber !== 0) {
return}
var message = 'Dear ' + recipient + ',\n\n'+ 'You have ' +
refillsNumber + ' remaining would you like to buy more? If not then
would you like to end your subsription?' + '\n\n' + 'Kind regards,'
+ '\n\n' + 'The revol team.';
var subject = 'Refill reminder';
MailApp.sendEmail(email,subject,message);
return
}
// in addition to this script which aims to send an email to the
customer when they only have 2 refill remaining -
/// I also want to set up a function that sends an email when they
have 0 refills remaining
和__eq__方法的类的实例。
__hash__类型的对象不可哈希。
出现此错误的原因是因为list是列表列表。
侧面说明：可哈希表示在python中不可变
您需要嵌套的迭代：
first first_output = [[mapka[letter] for letter in word] for word in first]
也是如此。您还可以循环第一和第二步，以避免代码重复
答案 1 :(得分：0)
由于mapka将应用于字符，因此您应该在字符级别进行迭代。
在python中，迭代 string 会导致遍历字符。
所以这应该起作用：
data = ["hokejistov hokej", "strelena strela", "trener trenuje"]
second = [[1, 2, 3, 4, 5], [7, 8, 10, 4, 11, 13], [8, 10, 4, 12, 14, 5, 4]]
mapka = {'h':1,'o':2,'k':3, 'e':4, 'j':5, 'i':6, 's':7, 't':8,'v':9,
'r':10, 'l':11, 'n':12, 'a':13, 'u':14}
first = [[word.lower() for word in text.split()[0]]for text in data]
second = [[word.lower() for word in text.split()[1]]for text in data]
print([[mapka[letter] for letter in word] for word in first])
print([[mapka[letter] for letter in word] for word in second])
答案 2 :(得分：0)
这是仅包含列表的解决方案：
# pretend to read your file
data = ["hokejistov hokej","strelena strela","trener trenuje"]
# a dictionary is not strictly needed here
mapka = "hokejistvrlnau"
# convert lines to columns
columns = []
for line in data:
for i,word in enumerate(line.split()):
try:
columns[i].append(word)
except IndexError:
columns.append([word])
print(columns) # [['hokejistov', 'strelena', 'trener'], ['hokej', 'strela', 'trenuje']]
# look up each letter
for column in columns:
print( [ [mapka.index(letter)+1 for letter in word] for word in column] )
# [[1, 2, 3, 4, 5, 6, 7, 8, 2, 9], [7, 8, 10, 4, 11, 4, 12, 13], [8, 10, 4, 12, 4, 10]]
# [[1, 2, 3, 4, 5], [7, 8, 10, 4, 11, 13], [8, 10, 4, 12, 14, 5, 4]]