Question

如何修改以下代码，以使其打印包含给定列表中项目因素的单独列表？

n = [3,4,5]
for i in n:
    print('Factors of ', i)
    for j in range(1,i+1):
        if i%j == 0:
           print(j)

Answer 1

我会使用一个简单的factors函数，然后执行循环

def factors(n):
    """Not the most optimal solution"""
    return [i for i in range(1, n+1) if not n % i]

n = [3, 4, 5]
for i in n:
    print(f'Factors of {i} = {factors(i)}')

输出

Factors of 3 = [1, 3]
Factors of 4 = [1, 2, 4]
Factors of 5 = [1, 5]

Answer 2

这对我有用：

hash

结果：

n = [3,4,5]
for i in n:
    print('Factors of ', i)
    remaining = i
    while remaining > 1 :
        for j in range(2,remaining+1):
            if remaining%j == 0:
               print(j)
           remaining /= j

与Linux命令('Factors of ', 3) 3 ('Factors of ', 4) 2 2 ('Factors of ', 5) 5 >>>巧合地工作：

factor

Answer 3

我对您的代码进行了一些重构，以使其更具可读性和易懂性：

n = [3, 4, 5]

def get_factors(num):
    result = []
    for i in range(1, num+1):
        if num % i == 0:
            result.append(i)
    return result

print([get_factors(elem) for elem in n])

让我知道这是否回答了您的问题吗？

遍历列表，以便为包含该项目因子的每个项目打印新列表

3 个答案: