遇到PHP错误 严重程度:通知
消息:只能通过引用分配变量
**这是我的控制器代码**
public function data_backup()
{
$this->load->dbutil();
$prefs = array('format' => 'zip','filename' => 'nirmithi.sql');
$backup =& $this->dbutil->backup($prefs);
$db_name = 'backup-on-'. date("Y-m-d-H-i-s") .'.zip';
$save = 'Backup/'.$db_name;
$this->load->helper('file');
write_file($save, $backup);
$this->load->helper('download');
force_download($db_name, $backup);
}
答案 0 :(得分:1)
删除并在此行尝试
$backup = $this->dbutil->backup($prefs);