Question

我想知道如何使用包含参数ex。的URL在php中进行curl请求：

URL.tld / test.php？paramenter = test

curl-request仅必须请求对该URL的http访问，然后再次关闭。

先谢谢您。

Answer 1

获取请求，例如：

<?php

$query = http_build_query([
 'param1' => 'value1',
 'param2' => 'value2',
]);

$url = "http://example.com/?".$query;

$curl = curl_init();

curl_setopt_array($curl, array(
  CURLOPT_URL => $url,
  CURLOPT_RETURNTRANSFER => true,
  CURLOPT_ENCODING => "",
  CURLOPT_MAXREDIRS => 10,
  CURLOPT_TIMEOUT => 30,
  CURLOPT_HTTP_VERSION => CURL_HTTP_VERSION_1_1,
  CURLOPT_CUSTOMREQUEST => "GET",
  CURLOPT_HTTPHEADER => array(
    "cache-control: no-cache"
  ),
));

$response = curl_exec($curl);
$err = curl_error($curl);

curl_close($curl);

if ($err) {
  echo "cURL Error #:" . $err;
} else {
  echo $response;
}

PHP中的卷曲请求>带参数的URL？

1 个答案: