所以我在Oracle数据库中有两列:
Name / count
我想将姓名打印x次,x是计数。
E.g. Paul / 5 would mean Paul being printed 5 times.
Sam / 6 would mean Sam being printed 6 times
尝试过row_number
,但不确定其工作原理吗?
答案 0 :(得分:1)
您需要递归查询才能实现。
with cte(nam, ctr) as (
select 'Paul' as nam, 5 as ctr from dual
union all
select 'Sam', 6 as ctr from dual
),
cte2(nam, ct, ctr) as (
select nam, 1 as ct, ctr from cte
union all
select nam, ct + 1, ctr from cte2
where ct<ctr
)select nam, ct from cte2
order by nam asc
输出:
请参见sqlfiddle
答案 1 :(得分:1)
您可以按以下方式使用connect:
SQL> WITH YOUR_TABLE AS
2 (SELECT 'paul' as NAME, 5 AS COUNT FROM DUAL UNION ALL
3 SELECT 'sam' as NAME, 6 AS COUNT FROM DUAL
4 ) -- YOUR ACTUAL QUERY STARTS FROM LINE#5
5 Select t.name, m.lvl
6 from your_table t
7 join
8 (Select level as lvl
9 from
10 (Select max(count) as maxcount
11 from your_table)
12 Connect by level <= maxcount) m
13 On (t.count >= m.lvl)
14 ORDER BY 1,2;
NAME LVL
---- ----------
paul 1
paul 2
paul 3
paul 4
paul 5
sam 1
sam 2
sam 3
sam 4
sam 5
sam 6
11 rows selected.
SQL>
干杯!
答案 2 :(得分:1)
这将起作用:
select name
from Table1,
(select level lvl
from dual
connect by level <= (select max(cnt) from Table1 )
)
where lvl <= cnt
order by name;
检查小提琴:http://sqlfiddle.com/#!4/14a67/1
谢谢!
答案 3 :(得分:1)
还有另一个选择(您的查询从第4行开始):
SQL> with your_table as
2 (select 'paul' as name, 5 as count from dual union all
3 select 'sam' as name, 6 as count from dual)
4 select name
5 from your_table cross join table (cast (multiset (select level from dual
6 connect by level <= count
7 ) as sys.odcinumberlist));
NAME
----
paul
paul
paul
paul
paul
sam
sam
sam
sam
sam
sam
11 rows selected.
SQL>
答案 4 :(得分:1)