请考虑以下事项:
public class MyObject
{
public bool B;
public string Txt;
}
List<MyObject> list; //list of a bunch of MyObject's
使用lambda表达式,如何生成由这些对象的Txt的逗号分隔值组成的字符串,其中B为真?
谢谢。
答案 0 :(得分:48)
for .net 3.5:
string.Join(",", list.Where(o => o.B).Select(o => o.Txt).ToArray())
for .net 4.0:
string.Join(",", list.Where(o => o.B).Select(o => o.Txt))
答案 1 :(得分:3)
string myString = string.Join(",", list.Where(x => x.B).Select(x=>x.Txt));
答案 2 :(得分:-2)
var strFinal = "";
myList.ForEach(pq => strFinal += ", " + pq.ItemId);