Question

请我需要帮助，我正在Laravel上的一个项目中，当T尝试以多对多方式使用数据透视表时遇到了问题

在我的category model Category.php中，我具有以下功能

public function users()
{
    return $this->belongsToMany(user::class);
}

在我的user model User.php中，我具有以下功能

public function authors()
{
    return $this->belongsToMany(author::class);
}

在web.php中，我有这个

Route::post('/onboarding', 'OnboardsController@categoryUser');

在我的onboarding view中，我有一个表格：

   <form action="{{ url('/onboarding') }}" method="POST">
    @csrf
      @foreach($categories as $category)
        <div class="radio-item">
        <input class="form control" name="category_id" type="checkbox" id="category_id" required>
          <label for="name">{{ $category -> title }}</label>
        </div>
        @endforeach

        <div class="form-row">
          <div class="form-group col-md-12 text-center">
            <button type="submit">Proceed to Authors</button>
          </div>
        </div>
      </form>

在我的OnboardsController

我有这个

public function categoryUser (Request $request)
{
  $user = User::findOrFail(Auth::user()->id);
  $user = categories()->attach($request->input('category_id'));

  return redirect ( route ('onboarding_author')); 
}

这是返回的错误：

调用未定义函数App \ Http \ Controllers \ categories（）

当我将控制器中的代码更改为

$category = Category::find($request->input('category_id'));
$user = User::where('user_id', Auth::id());
$category->users()->attach($user->id);

这是返回的错误：

调用未定义函数App \ Http \ Controllers \ users（）

这是我完整的OnboardsController.php代码

<?php

namespace App\Http\Controllers;
use Illuminate\Support\Facades\Auth;
use Illuminate\Http\Request;
use App\Author;
use App\User;
use App\Category;


class OnboardsController extends Controller
{
public function index()
        {
    //
    return view('onboarding')
    ->with('categories', Category::all());

}

public function author()
{
//
return view('onboarding_author')
->with('authors', Author::all());

}

public function categoryUser (Request $request)
{

    dd(request('category_id'));
    Category::findOrFail(request('category_id'))
    ->users()
    ->attach(auth()->user()->id);

    return redirect ( route ('onboarding_author')); 
}

请问我是Laravel的新手，我已经做了3天了，我不知道该如何解决。我需要帮助。

Answer 1

您的问题就在这里

$user = User::findOrFail( Auth::user()->id );
$user = categories()->attach($request->input('category_id'));
//      ^^^^^^^^^^^^

您在...上调用方法category（）？什么都没有。我假设您想在categories()模型中调用User.php方法。因此，尝试像这样更新代码：

$user = User::findOrFail( Auth::user()->id );
$user->categories()->attach($request->input('category_id'));
//      ^^^^^^^^^^^^

这样，您将关联两个对象。

旁注

正如我所提到的，我假设您在categories模型中拥有User方法：

# User.php

public function categories()
{
    return $this->belongsToMany(Category::class);
}

请记住，模型应该大写。

此外，您可以改进代码，直接从Auth外观获取用户

此：

$user = User::findOrFail(Auth::user()->id);

等同于：

$user = Auth::user();

Answer 2

您可以通过以下方法实现此目标：

$counter_connected = true;
$link = mysqli_connect($counter_host, $counter_user, $counter_password, $counter_database);
if (!$link) {
    $counter_connected = false;
    die('Connect Error (' . mysqli_connect_errno() . ') ' . mysqli_connect_error());
    exit;
}

if ($counter_connected == true) {
    $db = mysqli_connect($counter_host, $counter_user, $counter_password, $counter_database);
    $query = "SELECT * FROM CanadaPostal";
    $result = $db->query($query) or die(mysql_error());

    if ($result->num_rows > 0) {
        while($row = $result->fetch_assoc()) {
            $latitude = $row['latitude'];
            $longitude = $row['longitude'];
            $id = $row['id'];
            $googlemapKey = "[MY-KEY]";
            $json = file_get_contents('https://maps.googleapis.com/maps/api/geocode/json?latlng='.trim($latitude).','.trim($longitude).'&sensor=true&key='.$googlemapKey.'');
            $data = json_decode($json, true);
            $counter = 0;

            foreach ($data['results'] as $item) {
                if( $counter == 0 ) { 
                    if( !empty( $item['formatted_address'] ) ){
                        $formatted_address = $item['formatted_address'];
                        $query.$counter = "UPDATE CanadaPostal SET fulladd='".$item['formatted_address']."' WHERE id=".trim($id)."";
                        $result = $db->query($query.$counter) or die(mysql_error());
                    }
                }      
            $counter = $counter + 1; 
            }
        }
    }
}

在这里，您通过请求的public function categoryUser() { Category::findOrFail(request('category_id')) ->users() ->attach(auth()->user()->id); return redirect(route('onboarding_author')); }得到了Category，并附加了登录的用户（使用category_id助手来获得用户的auth()）。

调用Laravel中未定义的函数App \ Http \ Controllers \ categories（）

2 个答案:

旁注