Question

这是我的数据

var tabledata = {
0: {Name: "Server1", PRPName: "NO_PRP", OperatingSystem: "Linux", SLA: "SILVER", Environment: "Accept"}
1: {Name: "Server2", PRPName: "services", OperatingSystem: "Linux", SLA: "SILVER", Environment:"Accept"}
2: {Name: "Server3", PRPName: "NO_PRP", OperatingSystem: "Windows", SLA: "GOLD", Environment: "Accept"}
3: {Name: "Server4", PRPName: "services", OperatingSystem: "Linux", SLA: "GOLD", Environment: "Accept"}
4: {Name: "Server5", PRPName: "NO_PRP", OperatingSystem: "Windows", SLA: "GOLD", Environment: "Accept"}
5: {Name: "Server6", PRPName: "sql", OperatingSystem: "Windows", SLA: "GOLD", Environment: "Accept"}
6: {Name: "Server7", PRPName: "services", OperatingSystem: "Linux", SLA: "GOLD", Environment: "Production"}
7: {Name: "Server8", PRPName: "NO_PRP", OperatingSystem: "Windows", SLA: "GOLD", Environment: "Production"}
8: {Name: "Server9", PRPName: "sql", OperatingSystem: "Windows", SLA: "GOLD", Environment: "Production"}

我需要从Name：创建一个列表，像这样。

servernames = ["Server1","Server2","Server3","Server4","Server5","Server6","Server7","Server8"]

Answer 1

正如其他人所指出的，您有一个JavaScript对象（数字和代表服务器数据的对象之间的映射），而不是JSON。

要从此对象获取服务器名称，可以使用Object.values首先提取包含服务器信息的对象的属性值，然后使用map仅获取服务器名称，并使用以下内容生成一个数组：

var tabledata = {
  0: {Name: "Server1", PRPName: "NO_PRP", OperatingSystem: "Linux", SLA: "SILVER", Environment: "Accept"},
  1: {Name: "Server2", PRPName: "services", OperatingSystem: "Linux", SLA: "SILVER", Environment:"Accept"},
  2: {Name: "Server3", PRPName: "NO_PRP", OperatingSystem: "Windows", SLA: "GOLD", Environment: "Accept"},
  3: {Name: "Server4", PRPName: "services", OperatingSystem: "Linux", SLA: "GOLD", Environment: "Accept"},
  4: {Name: "Server5", PRPName: "NO_PRP", OperatingSystem: "Windows", SLA: "GOLD", Environment: "Accept"},
  5: {Name: "Server6", PRPName: "sql", OperatingSystem: "Windows", SLA: "GOLD", Environment: "Accept"},
  6: {Name: "Server7", PRPName: "services", OperatingSystem: "Linux", SLA: "GOLD", Environment: "Production"},
  7: {Name: "Server8", PRPName: "NO_PRP", OperatingSystem: "Windows", SLA: "GOLD", Environment: "Production"},
  8: {Name: "Server9", PRPName: "sql", OperatingSystem: "Windows", SLA: "GOLD", Environment: "Production"}
};
var servernames = Object.values(tabledata).map((server) => server.Name);

console.log(servernames);

Answer 2

尝试这个：

var tabledata = {
0: {Name: "Server1", PRPName: "NO_PRP", OperatingSystem: "Linux", SLA: "SILVER", Environment: "Accept"},
1: {Name: "Server2", PRPName: "services", OperatingSystem: "Linux", SLA: "SILVER", Environment:"Accept"},
2: {Name: "Server3", PRPName: "NO_PRP", OperatingSystem: "Windows", SLA: "GOLD", Environment: "Accept"},
3: {Name: "Server4", PRPName: "services", OperatingSystem: "Linux", SLA: "GOLD", Environment: "Accept"},
4: {Name: "Server5", PRPName: "NO_PRP", OperatingSystem: "Windows", SLA: "GOLD", Environment: "Accept"},
5: {Name: "Server6", PRPName: "sql", OperatingSystem: "Windows", SLA: "GOLD", Environment: "Accept"},
6: {Name: "Server7", PRPName: "services", OperatingSystem: "Linux", SLA: "GOLD", Environment: "Production"},
7: {Name: "Server8", PRPName: "NO_PRP", OperatingSystem: "Windows", SLA: "GOLD", Environment: "Production"},
8: {Name: "Server9", PRPName: "sql", OperatingSystem: "Windows", SLA: "GOLD", Environment: "Production"}
}

const result = Object.keys(tabledata).map(el => tabledata[el].Name)
console.log(result)

Answer 3

您的JSON：

var tabledata = {
"0": {Name: "Server1", PRPName: "NO_PRP", OperatingSystem: "Linux", SLA: "SILVER", Environment: "Accept"},
"1": {Name: "Server2", PRPName: "services", OperatingSystem: "Linux", SLA: "SILVER", Environment:"Accept"},
"2": {Name: "Server3", PRPName: "NO_PRP", OperatingSystem: "Windows", SLA: "GOLD", Environment: "Accept"},
"3": {Name: "Server4", PRPName: "services", OperatingSystem: "Linux", SLA: "GOLD", Environment: "Accept"},
"4": {Name: "Server5", PRPName: "NO_PRP", OperatingSystem: "Windows", SLA: "GOLD", Environment: "Accept"},
"5": {Name: "Server6", PRPName: "sql", OperatingSystem: "Windows", SLA: "GOLD", Environment: "Accept"},
"6": {Name: "Server7", PRPName: "services", OperatingSystem: "Linux", SLA: "GOLD", Environment: "Production"},
"7": {Name: "Server8", PRPName: "NO_PRP", OperatingSystem: "Windows", SLA: "GOLD", Environment: "Production"},
"8": {Name: "Server9", PRPName: "sql", OperatingSystem: "Windows", SLA: "GOLD", Environment: "Production"}
};

您可以使用Object.values获取表数据对象的值数组，然后应用Array.prototype.map将值转换为服务器名称，如下所示：

const serverNames = Object.values(tabledata).map((server) => server.Name);
console.log(serverNames);

它将打印：

["Server1", "Server2", "Server3", "Server4", "Server5", "Server6", "Server7", "Server8", "Server9"]

从JavaScript对象生成列表

3 个答案: