Question

我是SQL的新手，我不知道该怎么做。我想对类似对（vin，action）求和一个名为“ total_spending”的汇总，并选择第一个Dealer_name和参考月份年份（这样它就不会创建重复项），并具有类似示例的输出：输入


    from tkinter import *
    import tkinter as tk
    from tkinter.messagebox import *

    global my_list
    my_list = ["This is the first sentence , ", "This is the second sentence ,", "this is the third sentence ,", "this is the last sentence "]

    def show_answer():
        Ans = my_list
        blank.insert(0, Ans)


    main = Tk()
    main.title('Programm')
    main.geometry('500x500+300+100')

    Button(main, text='Show', command=show_answer).grid(row=30, column=1, sticky=W, pady=4)

    Label(main, text="The text is").grid(row=2)
    blank = Entry(main)
    blank.grid(row=2, column=1, ipadx=50, ipady=50, sticky="NW")

    mainloop()

输出

action  dealer_name   vin    Total_spending reference month year 
A1      D1            V1         T1             R1     M1    Y1
A2      D2            V2         T2             R1     M1    Y1
A2      D2            V2         T3             R2     M2    Y2
A3      D2            V1         T4             R1     M1    Y1
A4      D1            V2         T5             R1     M1    Y1
A2      D1            V2         T6             R1     M1    Y1
A1      D1            V1         T7             R2     M2    Y2
A4      D1            V2         T8             R2     M2    Y2
A1      D1            V1         T9             R3     M3    Y3
A3      D2            V2         T10            R1     M1    Y1
A3      D2            V1         T11            R2     M2    Y2

Answer 1

您可以在下面尝试-

select action,dealer_name,vin,sum(Total_spending) as total_spending, reference ,month, year
from tablename
group by action,  dealer_name ,  vin,reference ,month, year

SQL如何对唯一键对的列求和

1 个答案: