我在android中实现Twitter api,我已经生成了新的api和消费者密钥,但是这会返回错误“这个事件只是消费者密钥错误或签名不同”。
代码: OAUTHREquestTokenTask.java
package com.ex.softZilla;
import oauth.signpost.OAuthConsumer;
import oauth.signpost.OAuthProvider;
import android.content.Context;
import android.content.Intent;
import android.net.Uri;
import android.os.AsyncTask;
import android.util.Log;
/**
* An asynchronous task that communicates with Twitter to
* retrieve a request token.
* (OAuthGetRequestToken)
*
* After receiving the request token from Twitter,
* pop a browser to the user to authorize the Request Token.
* (OAuthAuthorizeToken)
*
*/
public class OAuthRequestTokenTask extends AsyncTask<Void, Void, Void> {
final String TAG = getClass().getName();
private Context context;
private OAuthProvider provider;
private OAuthConsumer consumer;
/**
*
* We pass the OAuth consumer and provider.
*
* @param context
* Required to be able to start the intent to launch the browser.
* @param provider
* The OAuthProvider object
* @param consumer
* The OAuthConsumer object
*/
public OAuthRequestTokenTask(Context context,OAuthConsumer consumer,OAuthProvider provider) {
this.context = context;
this.consumer = consumer;
this.provider = provider;
}
/**
*
* Retrieve the OAuth Request Token and present a browser to the user to authorize the token.
*
*/
@Override
protected Void doInBackground(Void... params) {
try {
Log.i(TAG, "Retrieving request token from Google servers");
final String url = provider.retrieveRequestToken(consumer, Constants.OAUTH_CALLBACK_URL);
Log.i(TAG, "Popping a browser with the authorize URL : " + url);
Intent intent = new Intent(Intent.ACTION_VIEW, Uri.parse(url)).setFlags(Intent.FLAG_ACTIVITY_SINGLE_TOP | Intent.FLAG_ACTIVITY_NO_HISTORY | Intent.FLAG_FROM_BACKGROUND);
context.startActivity(intent);
} catch (Exception e) {
Log.e(TAG, "Error during OAUth retrieve request token", e);
}
return null;
}
}
答案 0 :(得分:2)
我也遇到了同样的问题。我认为这是因为Twitter将请求令牌网址从http://api.twitter.com/oauth/request_token更改为http://twitter.com/oauth/request_token,因此请求令牌网址。
但官方文档称请求令牌网址为http://api.twitter.com/oauth/request_token。但示例应用程序失败了。我认为这是他的理由。