将列表拆分为n元组

Question

如何将列表拆分为指定长度的元组/列表列表？ splitBy :: Int - ＆gt; [a] - ＆gt; [[α]]

splitBy 2“asdfgh”应该返回[“as”，“df”，“gh”]

Answer 1

splitEvery通常会得到这份工作的认可。

Answer 2

在Hoogle中搜索Int -> [a] -> [[a]]得出chunksOf，这可能是有用的。

Answer 3

一种方法：

splitBy :: Int -> [a] -> [[a]]
splitBy _ [] = []
splitBy n xs = take n xs : splitBy n (drop n xs)

另一种方法：

splitBy' :: Int -> [a] -> [[a]]
splitBy' _ [] = []
splitBy' n xs = fst split : splitBy' n (snd split)
                where split = splitAt n xs