Question

只是想知道是否有人可以帮助我理解为什么我的代码没有输出数据。我在Microsoft SQL Server 2008中创建了一个T-SQL查询。查询工作正常，并在SQL管理工作室中显示所有正确的数据。以下是SQL Server Management studio中数据的外观：

block sequence|number of ties|percent_of_q4|number of q3 ties|percent of q3 ties| quality
0 1108  11.34296 37  3.33935 1
1 1094  31.11517  66 6.032907  1
2 1109  21.633 53  4.77908 1

当我尝试使用完全相同的查询在简单的PHP脚本中输出数据时，不会显示任何数据。

这是否因为sqlsrv_query不喜欢我的查询而发生？ sqlsrv_fetch_array在我的查询中不喜欢“IS NOT NULL”吗？我已经完全没有关于尝试什么的想法...任何人都可以提供任何建议，为什么这个相当简单的脚本似乎不起作用？任何回复将不胜感激！

如果有任何不清楚的地方，请告诉我。

干杯，尼尔

PHP脚本如下：

       <?php

        /*data base connection */



        $serverName = ".\SQLEXPRESS";

        $connectionOptions = array("Database"=>"V6_HOLLTS479_20101015_subset",

         "UID"=>"username",

         "PWD" => "password");



        /* Connect using Windows Authentication */       

        $conn = sqlsrv_connect($serverName, $connectionOptions);



        /* Check whether connnection is established */

        if($conn === false)

        {

            die(print_r(sqlsrv_errors(), true));

        }



        /* SQL query */

$tsql = "

DECLARE @block_size AS real



  DECLARE @threshold_1 AS real

 DECLARE @threshold_2 AS real

  DECLARE @threshold_3 AS real

 DECLARE @threshold_4 AS real







   --Set variables



    SET @block_size = 200.0



    SET @threshold_1 = 50  -- GISCat4HighThresh

    SET @threshold_2 = 75  -- GISCat3HighThresh

    SET @threshold_3 = 25  -- GISCat4LowThresh

    SET @threshold_4 = 50  -- GISCat3LowThresh



 SELECT

  sub_t.block_sequence ,

  sub_t.number_of_ties,

   tie_q_4.number_of_ties AS number_of_q4_ties,

   (CAST(tie_q_4.number_of_ties AS real)/CAST(sub_t.number_of_ties AS real))*100.0 AS percent_of_q4_ties,

       tie_q_3.number_of_ties AS number_of_q3_ties,

    (CAST(tie_q_3.number_of_ties AS real)/CAST(sub_t.number_of_ties AS real))*100.0 AS percent_of_q3_ties,



       --The next column shows the block quality.  This is currently 4,3,1 based on the threshold rules.

    CASE WHEN (

        (CAST(tie_q_4.number_of_ties AS real)/CAST(sub_t.number_of_ties AS real))*100.0 > @threshold_1

            OR

        (CAST(tie_q_3.number_of_ties AS real)/CAST(sub_t.number_of_ties AS real))*100.0 > @threshold_2

            ) THEN 4

        WHEN (

        (CAST(tie_q_4.number_of_ties AS real)/CAST(sub_t.number_of_ties AS real))*100.0 > @threshold_3

            OR

        (CAST(tie_q_3.number_of_ties AS real)/CAST(sub_t.number_of_ties AS real))*100.0 > @threshold_4

            ) THEN 3

        ELSE 1



                    END AS quality



        FROM (

        SELECT

            FLOOR(CAST(image_sequence AS real)/@block_size) AS block_sequence ,

            COUNT(image_sequence) AS number_of_ties

            FROM database

            GROUP BY 

                FLOOR(CAST(image_sequence AS real)/@block_size)

            ) AS SUB_T



        LEFT JOIN (

        SELECT FLOOR(CAST(image_sequence AS real)/@block_size) AS block_sequence ,

            COUNT(image_sequence) AS number_of_ties

            FROM database

            WHERE 

                quality = 4

            GROUP BY 

            FLOOR(CAST(image_sequence AS real)/@block_size)

        ) AS tie_q_4 ON sub_t.block_sequence = tie_q_4.block_sequence



        LEFT JOIN (

        SELECT

            FLOOR(CAST(image_sequence AS real)/@block_size) AS block_sequence ,

            COUNT(image_sequence) AS number_of_ties

            FROM  database

            WHERE 

                quality = 3

            GROUP BY 

            FLOOR(CAST(image_sequence AS real)/@block_size)

        ) AS tie_q_3 ON sub_t.block_sequence = tie_q_3.block_sequence


        WHERE sub_t.block_sequence IS NOT NULL
         ORDER BY block_sequence

";




$result = sqlsrv_query($conn, $tsql);



$row = sqlsrv_fetch_array($result, SQLSRV_FETCH_ASSOC);

print("<pre>");

print_r($row);

print("</pre>");

Answer 1

我遇到了类似的问题，我尝试了各种各样的问题，然后又回到了基础。如果你试试

$query=sqlsrv_query($conn, $tsql);
$result=sqlsrv_fetch_array($query);
print_r($result);

应该做的伎俩

PHP使用sqlsrv_query显示T-SQL语句

1 个答案: