Question

我是推送通知的新手，我设法使推送通知生效。现在，只要有推送通知到来，如果我按它，应用程序就会打开并进入页面。

这是我的推送通知消息

{"to":"eHPnnkSDzWk:APA91bHs...","data":{"message":"test notification","type":"5"}}

这些是类型

Gallery ( Type = 1 )
Messenger ( Type = 4 )
Events ( Type = 5 )
News ( Type = 6 )

这是我的didReceiveRemoteNotification函数

    func application(_ application: UIApplication, didReceiveRemoteNotification 
userInfo: [AnyHashable: Any],fetchCompletionHandler completionHandler: @escaping 
(UIBackgroundFetchResult) -> Void) {

        if let messageID = userInfo[gcmMessageIDKey] {
            print("Message ID: \(messageID)")
        }
        print(userInfo)

        completionHandler(UIBackgroundFetchResult.newData)
    }

这是我的问题，当用户单击推送通知时，如何从推送通知中获取此TYPE，然后在应用上打开特定页面？

（抱歉，这听起来很傻，但这是我第一次尝试这样做，我尝试环顾四周，但找不到正确的答案）

Answer 1

只需使用下面的代码即可通过测试

    func application(_ application: UIApplication, didReceiveRemoteNotification userInfo: [AnyHashable : Any]) {

        if let dict = userInfo as? [String:Any] {
            if let dataDict = dict["data"] as? [String:Any],let type = dataDict["type"] as? String{
                print(type)
            }
        }
    }

Answer 2

func userNotificationCenter(_ center: UNUserNotificationCenter, willPresent notification: UNNotification, withCompletionHandler completionHandler: @escaping (UNNotificationPresentationOptions) -> Void) {

    let userInfo = notification.request.content.userInfo

    guard
        let aps = userInfo[AnyHashable("aps")] as? NSDictionary,
        let alert = aps["alert"] as? NSDictionary,
        let body = alert["body"] as? String,
        let title = alert["title"] as? String
        else {
            // handle any error here
            return
        }

    print("Title: \(title) \nBody:\(body)")

    
    
}

如何在推送通知中获取数据？

2 个答案: