Question

我有一个用openJDK（Amazon Correto 11）和openJFX编写的应用程序。

当我在本地运行该应用程序时-一切正常。但是，当我从网络共享执行应用程序时，会出现异常：

java.lang.ExceptionInInitializerError
    at java.base/javax.crypto.JceSecurityManager.<clinit>(JceSecurityManager.java:65)
    at java.base/javax.crypto.Cipher.getConfiguredPermission(Cipher.java:2624)
    at java.base/javax.crypto.Cipher.getMaxAllowedKeyLength(Cipher.java:2646)
    at java.base/sun.security.ssl.SSLCipher.isUnlimited(SSLCipher.java:540)
    at java.base/sun.security.ssl.SSLCipher.<init>(SSLCipher.java:472)
    at java.base/sun.security.ssl.SSLCipher.<clinit>(SSLCipher.java:174)
    at java.base/sun.security.ssl.CipherSuite.<clinit>(CipherSuite.java:67)
    at java.base/sun.security.ssl.SSLContextImpl.getApplicableSupportedCipherSuites(SSLContextImpl.java:348)
    at java.base/sun.security.ssl.SSLContextImpl$AbstractTLSContext.<clinit>(SSLContextImpl.java:579)
    at java.base/java.lang.Class.forName0(Native Method)
    at java.base/java.lang.Class.forName(Class.java:315)
    at java.base/java.security.Provider$Service.getImplClass(Provider.java:1848)
    at java.base/java.security.Provider$Service.newInstance(Provider.java:1824)
    at java.base/sun.security.jca.GetInstance.getInstance(GetInstance.java:236)
    at java.base/sun.security.jca.GetInstance.getInstance(GetInstance.java:164)
    at java.base/javax.net.ssl.SSLContext.getInstance(SSLContext.java:168)
    at org.apache.http.ssl.SSLContexts.createDefault(SSLContexts.java:51)
    at org.apache.http.conn.ssl.SSLConnectionSocketFactory.getSocketFactory(SSLConnectionSocketFactory.java:194)
    at org.apache.http.impl.conn.PoolingHttpClientConnectionManager.getDefaultRegistry(PoolingHttpClientConnectionManager.java:115)
    at org.apache.http.impl.conn.PoolingHttpClientConnectionManager.<init>(PoolingHttpClientConnectionManager.java:122)
    at com.mashape.unirest.http.options.Options.refresh(Options.java:72)
    at com.mashape.unirest.http.options.Options.<clinit>(Options.java:46)
    at com.mashape.unirest.http.HttpClientHelper.prepareRequest(HttpClientHelper.java:151)
    at com.mashape.unirest.http.HttpClientHelper.request(HttpClientHelper.java:131)
    at com.mashape.unirest.request.BaseRequest.asString(BaseRequest.java:56)
    at myapp.util.MyTaxNumberValidator$3.run(MyTaxNumberValidator.java:185)
    at java.base/java.lang.Thread.run(Thread.java:834)
Caused by: java.lang.SecurityException: Can not initialize cryptographic mechanism
    at java.base/javax.crypto.JceSecurity.<clinit>(JceSecurity.java:120)
    ... 27 more
Caused by: java.lang.SecurityException: Can't read cryptographic policy directory: unlimited
    at java.base/javax.crypto.JceSecurity.setupJurisdictionPolicies(JceSecurity.java:326)
    at java.base/javax.crypto.JceSecurity$1.run(JceSecurity.java:111)
    at java.base/javax.crypto.JceSecurity$1.run(JceSecurity.java:108)
    at java.base/java.security.AccessController.doPrivileged(Native Method)
    at java.base/javax.crypto.JceSecurity.<clinit>(JceSecurity.java:107)
    ... 27 more

我使用以下命令运行应用程序：

\\\some-network-share\app\jre\bin\javaw.exe -jar myapp.jar

因为在此网络共享上，我已经复制了Amazon Correto 11 JDK文件和我用于该应用程序的其他库。

我在另一个线程中运行get请求，此线程引发异常。

我该如何克服这个问题？

请帮助。

我尝试了不同的库： 1. OkHttpClient 2. Java Unirest

，但两者都相同。


public class MyGetExecutor {


    public static void main(String[] args) {

        Thread getThread = new Thread( new Runnable() {

            @Override
            public void run() {

                try {
                    logMessage.add( "Before request" );
                    com.mashape.unirest.http.HttpResponse<String> response = Unirest.get("https://myappserver.domain.com/api/v1/users/1")
                    .header("User-Agent", "PostmanRuntime/7.17.1")
                    .header("Accept", "*/*")
                    .header("Cache-Control", "no-cache")
                    .header("Postman-Token", "abf4b45d-a2c5-4f53-b4e3-1fa29643d616,e59130fc-5ce0-4b70-af48-ab3808362e36")
                    .header("Host", "wf01.cdprojektred.com")
                    .header("Accept-Encoding", "gzip, deflate")
                    .header("Cookie", "JSESSIONID=2C71F035C2EDFF145FED5C03C4887EF1")
                    .header("Connection", "keep-alive")
                    .header("cache-control", "no-cache")
                    .asString();
                    logMessage.add( "After request" );
                } catch (Exception e) {
                    // TODO Auto-generated catch block
                    logMessage.add( "Exception in getThread: " + e.getMessage() );
                }


            }

        }, "Get-thread");
        getThread.setUncaughtExceptionHandler(
                new Thread.UncaughtExceptionHandler() {
                    @Override
                    public void uncaughtException(Thread t, Throwable e) {
                        logMessage.add( "Error in thread: " + e );
                        logMessage.add( "Details: " + e.getCause().getMessage() );
                    }
                }
            );
        getThread.start();

        while( getThread.isAlive() ) {

            try {
                Thread.sleep(1000);
                logMessage.add("Main thread sleeping...");
            } catch (Exception e) {
                logMessage.add("Exception in main thread...: " + e.getMessage());
            }



        }

    }
}

编辑1 我添加了其他堆栈跟踪-请检查

Answer 1

线索是您堆栈跟踪中的最后一个原因：
Caused by: java.lang.SecurityException: Can't read cryptographic policy directory: unlimited

下到兔子洞

通过在运行的JVM中检查java.security.properties来验证安全策略的来源：
```
System.getProperty("java.security.properties");
```
它应该存在并指向文件。检查该文件，并确保其具有以下属性crypto.policy=unlimited，并且策略文件所在的文件夹名为 unlimited 。策略文件本身应说明该文件夹的查找位置。

对于Coretto，它是<jre_home>/conf/security/policy/
您可以通过启动JVM并将其传递到策略文件的位置来修改安全策略的位置：
java -Djava.security.properties==/conf/security/java.security
OR
java -Djava.security.properties=/conf/security/java.security

在第一种情况下的其他=登录将导致Java仅使用您指向的文件中的属性。
第二个选项将添加/更新文件中定义的属性。
最后，您必须深入研究 Correto 11 ，以找到策略文件。
以上路径取自amazon-corretto-11.0.3.7.1-linux-x64.tar.gz

OpenJDK 11错误“无法初始化加密机制”

1 个答案:

下到兔子洞