Question

我正在为一个学校项目做这件事，需要知道为什么即使条件不满足，输出仍会不断吐出“爱沙尼亚”的声音。另外，为什么程序在某些地方没有显示“ None”？我不确定是应该包含所有代码还是仅包含部分代码，因此我将整件事放在以防万一。我是新来的，所以请保持我的学识...

# Purpose: Create a program that suggests a vacation spot based on user input


# Here is the Input, or answers to the questions
print('Hello! This is your Dream Vacation Spot!')
answers = [input('Do you want a "hot" or "cold" place? '),
        input('Do you want a place that has a "huge" pop or "small" pop? '),
        input('Are you planning on getting wet? "y" or "n": ')]

# Create the intro that displays what they said. 
def intro():
    for i in range(2):
        print('')
    print('Hi! Welcome to your Dream Vacation Spot!')
    print('')
    print('Listed here, are your answers:')
    print('Hot or cold place? You said ' + answers[0])
    print('Huge population, or small towny place? You said ' + answers[1])
    print('Want to get wet? You said ' + answers[2])
    for i in range(2):
        print('')

# Start using the if/ elif statements to decide places to go.
def main():
    if answers[0] == 'cold' and answers[1] == 'small' and answers[2] == 'wet' or 'Wet':
        one = 'Congrats!! You got... \n Estonia!'
        print(one)

    elif answers[0] == 'cold' or 'Cold' and answers[1] == 'big' or 'Big' and answers[2] == 'y' or 'Y':
        two = 'Congrats!! You got... \n Geirangerfjord, Norway!'
        print(two)

    elif answers[0] == 'cold' or 'Cold' and answers[1] == 'small' or 'Small' and answers[2] == 'n' or 'N':
        three = 'Congrats!! You got... \n Innsbruck, Austria!'
        print(three)

    elif answers[0] == 'cold' or 'Cold' and answers[1] == 'big' or 'Big' and answers[2] == 'n' or 'N':
        four = 'Congrats!! You got... \n Yellowknife, Canada!'
        print(four)

    elif answers[0] == 'hot' or 'Hot' and answers[1] == 'big' or 'Big' and answers[2] == 'n' or 'N':
        five = 'Congrats!! You got... \n Austin, Texas!'
        print(five)

    elif answers[0] == 'hot' or 'Hot' and answers[1] == 'small' or 'Small' and answers[2] == 'n' or 'N':
        six = 'Congrats!! You got... \n Bisbee, Arizona!'
        print(six)

    elif answers[0] == 'hot' or 'Hot' and answers[1] == 'small' or 'Small' and answers[2] == 'n' or 'N':
        seven = 'Congrats!! You got... \n Grand Junction, Colorado!'
        print(seven)

    elif answers[0] == 'hot' or 'Hot' and answers[1] == 'small' or 'Small' and answers[2] == 'y' or 'Y':
        eight = 'Congrats!! You got... \n Muskogee, Oklahoma!'
        print(eight)



def printAll():
    print(intro())
    print(main())
    for i in range(2):
        print('')
    print('Have a nice trip!!!')

printAll()

Answer 1

Ph！那是很多代码，关于如何处理复杂的逻辑，可能有很多很棒的课程，让我们看看我们是否不能仅仅使其变得更好一点。

首先，我建议您使用列表理解和lower（）函数来简化答案中的可能性

answers_lowercase = [x.lower() for x in answers]

然后为什么不在if / elif语句中使用单个逻辑测试，例如

def main():
    if answers_lowercase == ['cold', 'small', 'wet'] :
        print('Congrats!! You got... \n Estonia!')

可能还有更简洁的Python方式来编写代码：即从表中查找正确的答案，而不是使用六个“ if”语句；如果用户在输入中输入了错误的内容，则会进行错误处理。值得研究和学习的好东西。祝你好运！

Answer 2

如果需要，可以更改条件以使用“ in”关键字，以避免“ and”，“ or”之间的混淆例如。 （“冷”，“冷”）中的答案[0]和（“大”，“大”）中的答案[1]和（“ y”，“ Y”）中的答案[2]

Answer 3

您的问题在于if语句。当您检查or条件时，请用方括号将其包围。

例如answers[0] == ('cold' or 'Cold') and answers[1] == ('big' or 'Big') and answers[2] == ('y' or 'Y')

程序输出错误输出

3 个答案: