python opencv-对象跟踪和坐标

时间:2019-09-30 13:28:33

标签: python opencv

我正在使用对象跟踪代码。 https://www.pyimagesearch.com/2015/09/21/opencv-track-object-movement/。有几次它运行良好。它跟踪球很好。然后,打开相机没有问题,但是当我在相机的视范围内移动网球时,出现以下错误

if counter >= 10 and i == 1 and pts[-10] is not None:IndexError: deque index out of range

dX = pts[-10][0] - pts[i][0]
        dY = pts[-10][1] - pts[i][1]
        (dirX, dirY) = ("", "")

如果我删除if counter >= 10 and i == 1 and pts[-10] is not None:

代码工作时不显示x和y的位置,但这不是我想要的。可能是什么问题?

2 个答案:

答案 0 :(得分:0)

相同的问题(至少我是这样认为的)

一旦检测到此行,它就会崩溃

if counter >= 10 and i == 1 and pts[-10] is not None:

我的“解决方案”不好,它的准确性大大降低,但至少我可以运行而不会崩溃

将上面提到的行替换为

if (counter >= 10) and (i == 1):

,然后添加一个try / except块,其中将if块中的所有内容都放入其中。所以零件应该看起来像这样

if (counter >= 10) and (i == 1):
        try:
            if pts[-10] is not None:
                dX = pts[-10][0] - pts[i][0]
                dY = pts[-10][1] - pts[i][1]
                (dirX, dirY) = ("", "")

                if np.abs(dX) > 20:
                    dirX = "East" if np.sign(dX) == 1 else "West"

                if np.abs(dY) > 20:
                    dirY = "North" if np.sign(dY) == 1 else "South"

                if dirX != "" and dirY != "":
                    direction = "{}-{}".format(dirY, dirX)

            else:
                direction = dirX if dirX != "" else dirY

        except:
            direction = "error"

答案 1 :(得分:0)

检测轮廓后重置帧计数器:

# only proceed if at least one contour was found
if len(cnts) > 0:
    # find the largest contour in the mask, then use
    # it to compute the minimum enclosing circle and
    # centroid
    c = max(cnts, key=cv2.contourArea)
    ((x, y), radius) = cv2.minEnclosingCircle(c)
    M = cv2.moments(c)
    center = (int(M["m10"] / M["m00"]), int(M["m01"] / M["m00"]))


if len(pts) >= 60:
       cap.set(cv2.CAP_PROP_POS_FRAMES, 0)