如果对象为nil，则不应评估代码中的“无nil到字符串的隐式转换”

Question

这是代码：

if article.link && article.link.starts_with?(`https://www.youtube.com`) then article.link end

该错误涉及此部分：

article.link.starts_with?(`https://www.youtube.com`)

但是，如果article.link为nil，则甚至不应该评估该部分。

Answer 1

如果问题出在org.omg.CORBA.MARSHAL: Buffer overread by 4 bytes at org.openorb.io.AbstractInputStream.next(Unknown Source) at org.openorb.iiop.CDRInputStream.read_long(Unknown Source) at org.openorb.iiop.CDRInputStream.read_ulong(Unknown Source) at org.openorb.iiop.CDRInputStream.read_wstring(Unknown Source) at imap.TraceService.TraceTask_THelper.read(Unknown Source) at imap.TraceService._TraceService_ITFStub.getTaskById(Unknown Source) ，则错误将是article.link

实际上，问题出在NoMethodError: undefined method `starts_with?' for nil:NilClass表达式上。计算结果为https://www.youtube.com。为什么使用这些报价？将它们更改为nil或""