Question

我有一个URL可以给我这个结果：

{"status":"ok","result":[{"account":"11754-101","name":"test","channels":"15","billing":"1","billingstep":"60","increment":"0","credit":"1.0089"},{"account":"11754-102","name":"mult","channels":"15","billing":"1","billingstep":"60","increment":"0","credit":"2.7835"}]}

我正在尝试仅查看一个帐户的“信用”值。

Account: 11754-102
Credit: XXX

我执行的代码是这样，但似乎已损坏：

<?php
$json = '{"status":"ok","result":[{"account":"11754-101","name":"test","channels":"15","billing":"1","billingstep":"60","increment":"0","credit":"1.0089"},{"account":"11754-102","name":"mult","channels":"15","billing":"1","billingstep":"60","increment":"0","credit":"2.7835"}]}';

$apiResult = json_decode($json, true);
($apiResult['status'] !== 'ok') && 
  trigger_error('Unexpected API Result');

empty(($account = array_filter($apiResult['result'], function($item) {
  return $item['account'] === '11754-102';
}))) && trigger_error('Account not found.');

echo $account[0]['credit'];
?>

你能帮我吗？

Answer 1

当简单的^\w*?\d[a-zA-Z]*?[\s]?.*$可以使用快捷方式时，并不太喜欢使用快捷方式，但是主要的问题是，当您结束学习时，就会使用

if()

如果您查看echo $account[0]['credit'];的输出，在这种情况下，您将得到...

array_filter()

因此，尽管它只有一个元素，但它是元素1而不是0。

我已经重写了代码以将其纳入accounf（并添加了一些Array ( [1] => Array ( [account] => 11754-102 [name] => mult [channels] => 15 [billing] => 1 [billingstep] => 60 [increment] => 0 [credit] => 2.7835 ) )）...

if

Answer 2

由于我不知道您是否收到错误消息，因此如果要显示错误，可以使用本文来做：How do I get PHP errors to display?

问题是$account[0]不存在，$account["result"][0]存在。因此代码将为echo $account['result'][0]['credit'];

Answer 3

这是您的更正代码。您可以使用array_pop实现相同的目的。您的帐户的抵销金额为1，但您的提取金额为0。

<?php
$json = '{"status":"ok","result":[{"account":"11754-101","name":"test","channels":"15","billing":"1","billingstep":"60","increment":"0","credit":"1.0089"},{"account":"11754-102","name":"mult","channels":"15","billing":"1","billingstep":"60","increment":"0","credit":"2.7835"}]}';

$apiResult = json_decode($json, true);
($apiResult['status'] !== 'ok') &&
trigger_error('Unexpected API Result');

empty(($account = array_filter($apiResult['result'], function($item) {
    return $item['account'] === '11754-102';
}))) && trigger_error('Account not found.');

echo array_pop( $account )['credit'];
?>

使用JSON解码过滤结果

3 个答案: