Question

我有一个文本文件，其中包含一个唯一的文本，如vrf_name：** nVSatellite，该文本已存储在字典中。在这两者之间，一个vrf_name到即将到来的vrf_name包含一组我需要在列表中解析的行请为我提供解决方案。

VRF：** nVSatellite

 L    10.61.0.252/32 is directly connected, 9w5d, Bundle-Ether100.120
 C    10.61.76.240/31 is directly connected, 9w5d, Bundle-Ether50.120
 L    10.61.76.240/32 is directly connected, 9w5d, Bundle-Ether50.120
 O    223.224.150.16/32 [110/12] via 10.61.0.230, 5w4d, Bundle-Ether200.122

VRF：ePDG-IN

    L    10.61.0.252/32 is directly connected, 9w5d, Bundle-Ether100.120
 C    10.61.76.240/31 is directly connected, 9w5d, Bundle-Ether50.120
 L    10.61.76.240/32 is directly connected, 9w5d, Bundle-Ether50.120
 O    223.224.150.16/32 [110/12] via 10.61.0.230, 5w4d, Bundle-Ether200.122

VRF：JKIT-TL

   L    10.61.0.252/32 is directly connected, 9w5d, Bundle-Ether100.120
 C    10.61.76.240/31 is directly connected, 9w5d, Bundle-Ether50.120
 L    10.61.76.240/32 is directly connected, 9w5d, Bundle-Ether50.120
 O    223.224.150.16/32 [110/12] via 10.61.0.230, 5w4d, Bundle-Ether200.122

VRF：MST-LKAS

 .
 .
 .
 .

 dict = {}
  for index, line in enumerate(read_file()):
      match1 = re.search(r"VRF:", line)
      if match1:
          dict[index] = line

预期结果： VRF之间存在一行：需要在列表中进行解析

Answer 1

import re

d = {}

with open('vrf.txt') as file:
    lines = file.readlines()
    expr = re.compile(r'VRF:')
    first_match = None
    first_index = -1
    for index, line in enumerate(lines):
        next_match = expr.match(line)
        if next_match:
            if first_match:
                d[first_index] = lines[first_index: index]
            first_match = next_match
            first_index = index

Answer 2

不清楚您的输入文件是什么样子，以及您想从中保存什么。

顺便说一句，您要避免使用dict作为变量名。这是内置类型。

假设这样的输入-vrf_textfile.txt：

VRF: **nVSatellite
 L    10.61.0.252/32 is directly connected, 9w5d, Bundle-Ether100.120
 C    10.61.76.240/31 is directly connected, 9w5d, Bundle-Ether50.120
 L    10.61.76.240/32 is directly connected, 9w5d, Bundle-Ether50.120
 O    223.224.150.16/32 [110/12] via 10.61.0.230, 5w4d, Bundle-Ether200.122

VRF: ePDG-IN
 L    10.61.0.252/32 is directly connected, 9w5d, Bundle-Ether100.120
 C    10.61.76.240/31 is directly connected, 9w5d, Bundle-Ether50.120
 L    10.61.76.240/32 is directly connected, 9w5d, Bundle-Ether50.120
 O    223.224.150.16/32 [110/12] via 10.61.0.230, 5w4d, Bundle-Ether200.122

VRF: JKIT-TL
 L    10.61.0.252/32 is directly connected, 9w5d, Bundle-Ether100.120
 C    10.61.76.240/31 is directly connected, 9w5d, Bundle-Ether50.120
 L    10.61.76.240/32 is directly connected, 9w5d, Bundle-Ether50.120
 O    223.224.150.16/32 [110/12] via 10.61.0.230, 5w4d, Bundle-Ether200.122

代码：

with open(r"vrf_textfile.txt") as f:
    vrf_text = f.read() # This is read in as a single long string

vrf = {}
current_key = None

for index, line in enumerate(vrf_text.splitlines()):
    if line.startswith("VRF:"):
        vrf[index] = []
        current_key = index
    elif current_key is not None:
        if line.strip() != "": # I assume you don't want to include blank lines
            vrf[current_key].append(line)

# vrf is a dictionary of lists. Every key is a line number (int)
for line_number, lists in vrf.items():
    for item in lists:
        print(f"{line_number} - '{item}'")

输出：

0 - ' L    10.61.0.252/32 is directly connected, 9w5d, Bundle-Ether100.120'
0 - ' C    10.61.76.240/31 is directly connected, 9w5d, Bundle-Ether50.120'
0 - ' L    10.61.76.240/32 is directly connected, 9w5d, Bundle-Ether50.120'
0 - ' O    223.224.150.16/32 [110/12] via 10.61.0.230, 5w4d, Bundle-Ether200.122'
6 - ' L    10.61.0.252/32 is directly connected, 9w5d, Bundle-Ether100.120'
6 - ' C    10.61.76.240/31 is directly connected, 9w5d, Bundle-Ether50.120'
6 - ' L    10.61.76.240/32 is directly connected, 9w5d, Bundle-Ether50.120'
6 - ' O    223.224.150.16/32 [110/12] via 10.61.0.230, 5w4d, Bundle-Ether200.122'
12 - ' L    10.61.0.252/32 is directly connected, 9w5d, Bundle-Ether100.120'
12 - ' C    10.61.76.240/31 is directly connected, 9w5d, Bundle-Ether50.120'
12 - ' L    10.61.76.240/32 is directly connected, 9w5d, Bundle-Ether50.120'
12 - ' O    223.224.150.16/32 [110/12] via 10.61.0.230, 5w4d, Bundle-Ether200.122'

字典键作为行号以读取文本文件

2 个答案: