Question

如何使用另一个array过滤某些属性，如果匹配条件，它将返回另一个属性，例如：

Array1 = [{offenceCode: 'JLN14', offenceDesc:'Speeding'}]

Array2 = [{id:0, offenceCode: 'JLN14'}, {id:1, offenceCode: 'JLN13'}]

首先，我得到Array2并将属性offenceCode与Array1进行比较，如果属性相同，Array1应该返回OffenceDesc

这是我尝试过的：

  demo = [
    {
      offenceCode: 'JLN14',
      offenceType: '7',
      offenceDesc: 'emergency lane abuse'
    },
    {
      offenceCode: 'BRG04',
      offenceType: '8',
      offenceDesc: 'speeding'
    },
    {
      offenceCode: 'CRG04',
      offenceType: '9',
      offenceDesc: 'emergency lane abuse'
    }
  ];

  offenceCode: any;

  ngOnInit() {
    this.offenceCode = this.items.map(x => x.offenceCode1);
    console.log(this.offenceCode);
    if(this.demo.forEach(x => x.offenceCode === this.offenceCode)) {
      // return offenceDesc
    }
  }

目前我不知道如何解决这个问题，这是我的stackblitz demo，我可以就如何解决这个问题使用任何建议，如果有更好的实践，谢谢

Answer 1

您可以使用Array.prototype.findIndex进行此操作。

const matchIndex = this.demo.findIndex(x => x.offenceCode === this.offenceCode);
if(matchIndex !== -1) {
  return this.demo[matchIndex].offenceDesc;
}
return undefined;

请注意，findIndex如果找不到匹配项，将返回-1。

Answer 2

看起来您正在寻找：

offenceCode: string[];

ngOnInit() {
  this.offenceCode = this.items.map(x => x.offenceCode1);
  this.demo.forEach(x => {
    this.offenceCode
      .filter(e => e === x.offenceCode)
      .forEach(e => console.log(x.offenceDesc));
    });
}

进行以下修改：

您应将offenceCode定义为字符串[]
现在，您可以遍历demo数组并在上一行的 offenceCode 上执行过滤器。现在，满足条件的任何内容都会记录到控制台中（您可以根据需要进行更改）

Answer 3

ngOnInit(){
  let Array1 = [{offenceCode: 'JLN14', offenceDesc:'Speeding'}]
  let Array2 = [{id:0, offenceCode: 'JLN14'}, {id:1, offenceCode: 'JLN13'}]

  let object = Array1.filter(x => x.offenceCode == Array2.filter(y => y.offenceCode == x.offenceCode)[0].offenceCode)[0]

  return object ? object.offenceDesc ? null
}

过滤并比较带有条件的打字稿中的两个数组

3 个答案: