Question

我的代码如下：

int main(){
    int choice=(1,2,3);
    printf("1- Finabocci sequence\n");
    printf("2- Check valid date\n");
    printf("3- Quit\n");
    printf("Choose an operation: \n");
    scanf("%d", &choice);
    switch(choice){
    case 1:
    {
        int t1 = 0, t2 = 1, nextTerm = 0, n;
        printf("Enter a positive number: ");
        scanf("%d", &n);
        printf("Fibonacci Series: %d, %d, ", t1, t2);
        nextTerm = t1 + t2;
        while(nextTerm <= n)
        {
            printf("%d, ",nextTerm);
            t1 = t2;
            t2 = nextTerm;
            nextTerm = t1 + t2;
        }
        break;
    }


    case 2:
    {
        int validDate(int d,int m,int y){
            if (m<1||m>12) return 0; 
            else if (m==1||m==3||m==5||m==7||m==8||m==10||m==12){
                if (d>=1&&d<=31) return 1; 
                else return 0;
            }
            else if (m==4||m==6||m==9||m==11) {
                if (d>=1&&d<=30) return 1; 
                else return 0;
            }  
            else if (m==2) {
                if (y%400==0||(y%4==0&&y%100!=0)) {
                    if (d>=1&&d<=29) return 1;
                    else return 0;
                }
                else if (d>=1&&d<=28) return 1;
                else return 0;
            }
        }


        int main(int validDate(int d,int m,int y)) {
            int d,m,y;
            printf ("Input day: ");
            scanf("%d",&d);
            printf ("Input month: ");
            scanf("%d",&m);
            printf ("Input year: ");
            scanf("%d",&y);
            if(validDate(d,m,y)!=0) printf("valid date");
            else printf("invalid date");
            return 0;
        } 
        break;
    }
    default: printf("exit?");
        getchar();
    }
    return 0; 
}

我真的不知道option2根本没有运行，就像第一个和第三个一样。我该如何解决这个问题：D 例如：我单独运行Option2代码及其工作，但是当我放入交换机时，它将根本无法工作

Answer 1

您将主要功能称为主要功能。我为您修复了代码。

int main(){
int choice=(1,2,3);
printf("1- Finabocci sequence\n");
printf("2- Check valid date\n");
printf("3- Quit\n");
printf("Choose an operation: \n");
scanf("%d", &choice);
switch(choice){
    case 1:
{
    int t1 = 0, t2 = 1, nextTerm = 0, n;
    printf("Enter a positive number: ");
    scanf("%d", &n);
    printf("Fibonacci Series: %d, %d, ", t1, t2);
    nextTerm = t1 + t2;
    while(nextTerm <= n)
{
    printf("%d, ",nextTerm);
    t1 = t2;
    t2 = nextTerm;
    nextTerm = t1 + t2;
}
break;
}
case 2:
    {
       int validDate(int d,int m,int y){
    if (m<1||m>12) return 0; 
    else if (m==1||m==3||m==5||m==7||m==8||m==10||m==12){
    if (d>=1&&d<=31) return 1; 
    else return 0;
 }
 else if (m==4||m==6||m==9||m==11) {
    if (d>=1&&d<=30) return 1; 
    else return 0;
 }  
 else if (m==2) {
    if (y%400==0||(y%4==0&&y%100!=0)) {
        if (d>=1&&d<=29) return 1;
        else return 0;
         }
         else if (d>=1&&d<=28) return 1;
         else return 0;
        }
}

    int d,m,y;
    printf ("Input day: ");
    scanf("%d",&d);
    printf ("Input month: ");
    scanf("%d",&m);
    printf ("Input year: ");
    scanf("%d",&y);
    if(validDate(d,m,y)!=0) printf("valid date\n");
    else printf("invalid date \n");

}
     default: printf("exit?");
     getchar();
 }
    return 0; 
}

Answer 2

第一件事是int main(int validDate(int d,int m,int y))应该像这样int validDate(int d,int m,int y)
在您的情况下，这些代码不能像这样。

int choice=(1,2,3);-错误

int choice= 0;-对
另一件事是
1. nextTerm = t1 + t2;
  
  输出-：0,1,1,2,3->错误
2. nextTerm = t2 + 1;
  
  输出-：0,1,2,3->正确
另一件事是，在编译代码时，必须在每个break;和{{1 }}您已给
最后的事情是遵循好的编码方法。它还可以帮助您识别错误

此处为更正的代码

cases

我试图弄清楚选项＃2如何无法运行。 C编程

2 个答案: