Question

我无法使用return函数来打印最终值。我的代码：

    def filter_wave(wave,n):
        new_wave = [i for i in wave]
        for k in range(n):
            for i in range(len(wave)):
                curr_wave = new_wave.copy()
                if(i==0):
                    new_wave[i] = int(curr_wave[i]*0.6+curr_wave[i+1]*0.2)
                elif(i>0 and i<len(wave)-1):
                    new_wave[i] = int(curr_wave[i-1]*0.2+curr_wave[i]*0.6+curr_wave[i+1]*0.2)
                else:
                    new_wave[i] = int(curr_wave[i-1]*0.2+curr_wave[i]*0.6)
        print(new_wave)

迭代n次之后，它应该返回最后一波。 print()有效，但如果我尝试return，则无效。有什么错误吗？

Image of successful print()

Image of unsuccessful return

Answer 1

如果我正确理解了您的问题，那么您可以通过运行以下行来调用函数

filter_wave(original_wave_sample, 200)

您希望输出等于打印变量new_wave

当您在主体中使用print（）打印变量并且没有return语句时，该变量将被打印到屏幕上。如果使用return（new_wave），则必须指定一个变量，将在其中存储返回的变量new_wave：

函数中包含return（new_wave）

result = filter_wave(original_wave_sample, 200)
print(result)

完整示例：

 def filter_wave(wave,n):
    new_wave = [i for i in wave]
    for k in range(n):
        for i in range(len(wave)):
            curr_wave = new_wave.copy()
            if(i==0):
                new_wave[i] = int(curr_wave[i]*0.6+curr_wave[i+1]*0.2)
            elif(i>0 and i<len(wave)-1):
                new_wave[i] = int(curr_wave[i-1]*0.2+curr_wave[i]*0.6+curr_wave[i+1]*0.2)
            else:
                new_wave[i] = int(curr_wave[i-1]*0.2+curr_wave[i]*0.6)
    return(new_wave)

result = filter_wave(original_wave_sample, 200)
print(result)

我可以使用'print'打印出python列表，但不能使用return

1 个答案: