我在项目中使用jQuery nestedSortable plugin。移动列表项时,我序列化数组并将其保存到我的数据库。我无法从PHP数组重新创建HTML列表。可能是因为它已经晚了。 :)
我有以下PHP数组:
Array
(
[list_4] => root
[list_3] => 4
[list_1303966373] => 3
[list_1] => 1303966373
[list_5] => 1
[list_2] => 1
[list_6] => root
)
它应该列出类似......
的列表<ol>
<li id='list_4'>value 4
<ol>
<li id='list_3'>value 3
<ol>
<li id='list_1303966373'>value 1303966373
<ol>
<li id='list_1'>value 1
<ol>
<li id='list_5'>value 5</li>
<li id='list_2'>value 2</li>
</ol>
</li>
</ol>
</li>
</ol>
</li>
</ol>
</li>
<li id='list_6'>value 6</li>
</ol>
(忽略这些值,它们就在那里展示。)
HTML列表可以有任何深度的嵌套列表。
我的大脑已经死了,我无法上班。有人有建议吗?我永远欠你饼干。还有一座城堡。
感谢。 :)
答案 0 :(得分:4)
在这里你有它(你的样品测试正常):
<?php
$tree = array(
"list_4" => "root",
"list_3" => "list_4",
"list_1303966373" => "list_3",
"list_1" => "list_1303966373",
"list_5" => "list_1",
"list_2" => "list_1",
"list_6" => "root",
);
function getChildrenLists($tree){
$tree2 = array();
foreach($tree as $child => $parent){
if(!array_key_exists($parent, $tree2)) $tree2[$parent] = array();
$tree2[$parent][] = $child;
}
return $tree2;
}
function renderTree($tree2, $parent = "root"){
if($parent != "root") echo "<li id='$parent'> value $parent\n";
$children = $tree2[$parent];
if(count($children) > 0){ //If node has children
echo "<ol>\n";
foreach($children as $child)
renderTree($tree2, $child);
echo "</ol>\n";
}
if($parent != "root") echo "</li>\n";
}
$tree2 = getChildrenLists($tree);
renderTree($tree2);
?>
我想要我的饼干!呵呵。希望它有所帮助。