我当前的Android应用程序需要从本地Sqlite数据库中获取带有count字段的行。
我意识到我需要让我的DO实体定义此计数字段并@Ignore(ed)
我在Google上搜索并找到了这个page
@Entity
data class User(
@PrimaryKey val id: Int,
val firstName: String?,
val lastName: String?,
@Ignore val picture: Bitmap?
)
但是,当我将确切的Kotlin代码复制并粘贴到我的应用程序中时,由于这些异常而无法构建
database_room:kaptStagingDebugKotlin FAILED
e: /Users/rossulbricht/projects/silkroad/database_room/build/tmp/kapt3/stubs/stagingDebug/org/dread/pirate/database_room/model/User.java:7: error: Entities and POJOs must have a usable public constructor. You can have an empty constructor or a constructor whose parameters match the fields (by name and type).
public final class User {
^
Tried the following constructors but they failed to match:
User(int,java.lang.String,java.lang.String,android.graphics.Bitmap) -> [param:id -> matched field:id, param:firstName -> matched field:firstName, param:lastName -> matched field:lastName, param:picture -> matched field:unmatched]
e: /Users/rossulbricht/projects/silkroad/database_room/build/tmp/kapt3/stubs/stagingDebug/org/dread/pirate/database_room/model/User.java:9: error: Cannot find setter for field.
private final int id = 0;
^
e: /Users/rossulbricht/projects/silkroad/database_room/build/tmp/kapt3/stubs/stagingDebug/org/dread/pirate/database_room/model/User.java:11: error: Cannot find setter for field.
private final java.lang.String firstName = null;
^
e: /Users/rossulbricht/projects/silkroad/database_room/build/tmp/kapt3/stubs/stagingDebug/org/dread/pirate/database_room/model/User.java:13: error: Cannot find setter for field.
private final java.lang.String lastName = null;
^
w: [kapt] Incremental annotation processing requested, but support is disabled because the following processors are not incremental: androidx.room.RoomProcessor (DYNAMIC).
> Task :networking:mergeStagingDebugNativeLibs
> Task :android_idplus:generateStagingDebugRFile
> Task :networking:processStagingDebugManifest
FAILURE: Build failed with an exception.
我的问题是...
您如何忽略Kotlin数据类会议室实体中的列?
为什么Google android示例不起作用?
我正在使用
Android Studio 3.5
Build #AI-191.8026.42.35.5791312, built on August 9, 2019
JRE: 1.8.0_202-release-1483-b49-5587405 x86_64
JVM: OpenJDK 64-Bit Server VM by JetBrains s.r.o
macOS 10.14.6
buildscript {
ext.kotlin_version = '1.3.50'
repositories {
google()
jcenter()
}
dependencies {
classpath 'com.android.tools.build:gradle:3.5.0'
classpath "org.jetbrains.kotlin:kotlin-gradle-plugin:$kotlin_version"
}
}
allprojects {
repositories {
google()
jcenter()
maven {
url "https://sdk.smartlook.com/android/release"
}
}
}
ext {
compileSdkVersion = 28
targetSdkVersion = 28
minSdkVersion = 21
supportLibVersion = '1.1.0-beta01'
coreKtx = '1.2.0-alpha04'
materialMaterial = '1.1.0-alpha10'
legacySupportV4 = "1.0.0"
recyclerView = '1.1.0-beta04'
lifecycleExtensions = '2.2.0-alpha04'
playServicesAuthVersion = "16.0.1"
archLifecycleVersion = '2.2.0-alpha04'
roomVersion = '2.2.0-rc01'
archPagingVersion = '2.1.0'
archWorkerRuntimeVersion = '2.3.0-alpha01'
constraintLayoutVersion = '2.0.0-beta2'
browserVersion = '1.0.0'
appCompatVersion = '1.1.0'
junitVersion = "4.12"
testRunnerVersion = '1.1.0-alpha4'
espressoTestCoreVersion = '3.1.0-alpha4'
uiautomatorVersion = '2.2.0-alpha4'
leakcanaryVersion = "1.6.1"
commonsTextVersion = '1.7'
rxbinding2Version = "2.2.0"
picassoVersion = "2.71828"
retrofit2Version = '2.6.1'
rxAndroidVersion = '2.1.1'
rxJavaVersion = '2.2.11'
jacksonKotlinVersion = '2.10.0.pr1'
okhttp3Version = '4.1.1'
okioVersion = '2.4.0'
jakewRxrelay2Version = '2.1.0'
daggerVersion = '2.24'
numbusJoseJwtVersion = '7.1'
interComVersion = "5.4.1"
guavaAndroidVersion = "28.1-android"
}
task clean(type: Delete) {
delete rootProject.buildDir
}
allprojects {
gradle.projectsEvaluated {
tasks.withType(JavaCompile) {
options.compilerArgs << "-Xlint:unchecked" << "-Xlint:deprecation"
}
}
}
答案 0 :(得分:1)
这里
@Entity
data class User(
@PrimaryKey val id: Int,
val firstName: String?,
val lastName: String?,
@Ignore val picture: Bitmap?
)
对其进行修改,以使
@Entity
data class User(
@PrimaryKey val id: Int,
val firstName: String?,
val lastName: String?,
@Ignore val picture: Bitmap?
){
constructor():this(id=null,firstName=null,lastName=null,picture=null) }
然后会出现另一个错误,因为没有设置器,因此将val
替换为var
@Entity
data class User(
@PrimaryKey var id: Int,
var firstName: String?,
var lastName: String?,
@Ignore val picture: Bitmap?
){
constructor():this(id=null,firstName=null,lastName=null,picture=null) }
这是我用于房间的摇篮
implementation "androidx.room:room-runtime:$room_version"
kapt "androidx.room:room-compiler:$room_version"
implementation "androidx.room:room-rxjava2:$room_version"
implementation "androidx.room:room-ktx:$room_version"
在顶部添加apply plugin: 'kotlin-kapt'
ext.room_version = '2.2.0-rc01'
答案 1 :(得分:0)
该实体的值应为var data: String?
,并带有构造函数:
@Entity
data class User(
@PrimaryKey val id: Int,
var firstName: String?,
var lastName: String?,
@Ignore var picture: Bitmap?
){
constructor: this(firstName = "", lastName = "")
}
您当然可以做val
,但是您应该添加构造函数。
或者只是val
s:
@Entity
data class User(
@PrimaryKey val id: Int,
var firstName: String,
var lastName: String,
@Ignore var picture: Bitmap
)
实际上,@Ignore
与之无关。有关更多信息,请refer this article。
您不能真正同时拥有val
和null。房间不允许这样做。如果您希望变量为可空值,请坚持使用var
并按如上所述将构造函数添加到数据类中。
为什么Google android示例不起作用? 如果您从引用的页面检查数据类和代码,则会注意到这种差异。