所以我有这个从查询中得到的数组。当我print_r
Array
(
[0] => Array
(
[Name] => NAME 1
[Last] => LastValue1
[Bid] =>
[Ask] =>
)
[1] => Array
(
[Name] => NAME 1
[Last] =>
[Bid] => BidValue1
[Ask] =>
)
[2] => Array
(
[Name] => Name 2
[Last] => LastValue2
[Bid] => BidValue2
[Ask] =>
)
[3] => Array
(
[Name] => NAME 1
[Last] =>
[Bid] =>
[Ask] => AskValue1
)
[4] => Array
(
[Name] =>Name 2
[Last] =>
[Bid] =>
[Ask] => AskValue2
)
)
我想实现数组看起来像这样
Array
(
[0] => Array
(
[Name] => NAME 1
[Last] => LastValue1
[Bid] => BidValue1
[Ask] => AskValue1
)
[2] => Array
(
[Name] => Name 2
[Last] => LastValue2
[Bid] => BidValue2
[Ask] => AskValue2
)
)
我尝试这种方式(从Google获取)
$result = array();
foreach ($newArray as $element) {
$result[$element['Name']][] = $element;
}
echo "<pre>";print_r($result);
但是它没有显示我想要的结果。我该如何实现? 在此先感谢您,我的英语很抱歉
答案 0 :(得分:0)
您可以在以下代码段中使用相同的代码
$result = [];
foreach ($newArray as $element) {
foreach ($element as $key => $value) {
// checking if value for key is already added to result array
if ((!empty($result[$element['Name']]) && !array_key_exists($key, $result[$element['Name']])) || empty($result[$element['Name']])) {
if (!empty($value)) { // checking if value not empty
$result[$element['Name']] = ($result[$element['Name']] ?? []);
// merge it to group wise name result array
$result[$element['Name']] = array_merge($result[$element['Name']], [$key => $value]);
}
}
}
}
array_merge-合并一个或多个数组
array_key_exists —检查数组中是否存在给定的键或索引
输出:-
Array
(
[0] => Array
(
[Name] => NAME1
[Last] => LastValue1
[Bid] => BidValue1
[Ask] => AskValue1
)
[1] => Array
(
[Name] => Name2
[Last] => LastValue2
[Bid] => BidValue2
[Ask] => AskValue2
)
)
答案 1 :(得分:0)
这是将foreach
与array_filter
一起使用的最短和简单的解决方案
foreach($a as &$v){
$v = array_filter($v);
isset($r[$v['Name']]) ? ($r[$v['Name']] += $v) : ($r[$v['Name']] = $v);
}
您可以使用array_values
重新排列数组的顺序。