当输入值(正在设置的字段不是)为{{时,有什么方法可以应用Control-Lens-Setter.html#g:4中提到的组合器/设置器1}}?
例如,如果我具有以下条件,请考虑使用Just x
组合器:
(~+)
我想要一个执行以下操作的二传手:
let target = (1, 2)
input1 = Just 10
input2 = Nothing
在这种情况下,我尝试避免使用(11, 2) == target & (_1 . someSetter) +~ input1
& (_2 . someSetter) +~ input2
或fmap
,因为我要做很多这样的操作,并且宁愿通过利用镜头的简洁/简洁来避免样板
答案 0 :(得分:5)
您总是可以定义自己的设置器。
maybeSetter :: (b -> a -> a) -> ASetter s t a a -> Maybe b -> s -> t
maybeSetter g f x = runIdentity . f (Identity . maybe id g x)
(+!) :: Num a => ASetter s t a a -> Maybe a -> s -> t
(+!) = maybeSetter (+)
let target = (1, 2)
input1 = Just 10
input2 = Nothing
in
(11, 2) == target & (_1 . someSetter) +! input1
& (_2 . someSetter) +! input2
您还可以轻松定义其他设置器。
(-!) :: Num a => ASetter s t a a -> Maybe a -> s -> t
(-!) = maybeSetter subtract
(||!) :: ASetter s t Bool Bool -> Maybe Bool -> s -> t
(||!) = maybeSetter (||)
(<>!) :: Semigroup a => ASetter s t a a -> Maybe a -> s -> t
(<>!) = maybeSetter (flip (<>))
(.!) :: ASetter s t a a -> Maybe a -> s -> t
(.!) = maybeSetter const
(%!) :: ASetter s t a a -> Maybe (a -> a) -> s -> t
(%!) = maybeSetter id
那是镜头的妙处。它们只是常规功能。