SuiteScript2.0设置估算帐单地址有效，但收货地址无效

Question

我一直在尝试使用suitescript2.0在NetSuite的现有估算值上设置帐单和送货地址。我当前的代码

function createSalesOrderAddress(data){

    var estimate = data.record;
    log.debug("Address Parts", JSON.stringify(data));
    // set billing details
    estimate.setValue('billaddresslist',-2);
    var addr = estimate.getSubrecord('billingaddress');
    addr.setValue('country', 'AU');
    addr.setValue('isresidential', 'F');
    addr.setValue('attention', '');
    addr.setValue('addressee', data.address.firstname + " " + data.address.surname);
    addr.setValue('addr1', data.address.address1);
    addr.setValue('city', data.address.suburb);
    addr.setValue('state', data.address.state);
    addr.setValue('zip', data.address.postcode);
    estimate.setValue('billaddress', data.address.address1 + 'n' + data.address.suburb + ' ' + data.address.state + ' ' + data.address.postcode + 'nAustralia');
    //set shipping details
    estimate.setValue('shipaddresslist',-2);
    var shipaddr = estimate.getSubrecord('shippingaddress');
    shipaddr.setValue('country', 'AU');
    shipaddr.setValue('isresidential', 'F');
    shipaddr.setValue('attention', '');
    shipaddr.setValue('addressee', data.address.firstname + " " + data.address.surname);
    shipaddr.setValue('addr1', data.address.address1);
    shipaddr.setValue('city', data.address.suburb);
    shipaddr.setValue('state', data.address.state);
    shipaddr.setValue('zip', data.address.postcode);
    estimate.setValue('shipaddress', data.address.address1 + 'n' + data.address.suburb + ' ' + data.address.state + ' ' + data.address.postcode + 'nAustralia');

    return estimate;
}

当我注释掉设置送货地址的部分时，该代码可以很好地工作，但是对于送货部分，它将无法工作。设置收货地址的方式与设置帐单地址的方式是否有所不同？

我收到无用的错误 “ type”：“ error.SuiteScriptError”，“ name”：“ UNEXPECTED_ERROR”，“ message”：null