Question

我想打印一个模块的文档，以包含每个类和该类中每个方法的文档字符串，但只包括我编写的方法；不是默认方法。

这是my_module.py：

import json
import pandas as pd

class my_class1:
    """My class 1 docs."""

    def my_method1(self):
        """My class 1 method 1 docs."""
        return None

class my_class2:
    """My class 1 docs."""

    def my_method1(self):
        """My class 2 method 2 docs."""
        return None

所需的输出是这样

my_class1
My class 1 docs.

    my_method1:
    My class 1 method 1 docs.


my_class2
My class 2 docs.

    my_method2:
    My class 2 method 2 docs.

此脚本成功打印了我想要的所有类方法：

import my_module as mm
imports = ['json','pd']  # Pre-defined modules within my_module that I don't wish to document
for i in [c for c in dir(mm) if not c.startswith('__') and not c in imports]:
    print(getattr(mm, i).__name__)
    print(getattr(mm, i).__doc__)

输出：

my_class1
My class 1 docs.
my_class2
My class 1 docs.

但是我已经尝试过将该脚本包含方法，但是它只是多次记录每个类并排除了方法。

import my_module as mm
imports = ['json','pd']
for i in [c for c in dir(mm) if not c.startswith('__') and not c in imports]:
        print(getattr(mm, i).__name__)
        print(getattr(mm, i).__doc__)
        for j in [c for c in dir(i) if c == '__init__' or not c.startswith('__')]:
             print(getattr(mm, i,j).__name__)
             print(getattr(mm, i,j).__doc__)

输出：

my_class1
My class 1 docs.
my_class1
My class 1 docs.
my_class1
My class 1 docs.
my_class1
My class 1 docs.
my_class1
My class 1 docs.
my_class1
My class 1 docs.
my_class1
My class 1 docs.
my_class1
My class 1 docs.
my_class1
My class 1 docs.
my_class1
My class 1 docs.
my_class1
My class 1 docs.
my_class1
My class 1 docs.
my_class1
My class 1 docs.
my_class1
My class 1 docs.
my_class1
My class 1 docs.
my_class1
My class 1 docs.
my_class1
My class 1 docs.
my_class1
My class 1 docs.
my_class1
My class 1 docs.
my_class1
My class 1 docs.
my_class1
My class 1 docs.
my_class1
My class 1 docs.
my_class1
My class 1 docs.
my_class1
My class 1 docs.
my_class1
My class 1 docs.
my_class1
My class 1 docs.
my_class1
My class 1 docs.
my_class1
My class 1 docs.
my_class1
My class 1 docs.
my_class1
My class 1 docs.
my_class1
My class 1 docs.
my_class1
My class 1 docs.
my_class1
My class 1 docs.
my_class1
My class 1 docs.
my_class1
My class 1 docs.
my_class1
My class 1 docs.
my_class1
My class 1 docs.
my_class1
My class 1 docs.
my_class1
My class 1 docs.
my_class1
My class 1 docs.
my_class1
My class 1 docs.
my_class1
My class 1 docs.
my_class1
My class 1 docs.
my_class1
My class 1 docs.
my_class1
My class 1 docs.
my_class1
My class 1 docs.
my_class1
My class 1 docs.
my_class2
My class 1 docs.
my_class2
My class 1 docs.
my_class2
My class 1 docs.
my_class2
My class 1 docs.
my_class2
My class 1 docs.
my_class2
My class 1 docs.
my_class2
My class 1 docs.
my_class2
My class 1 docs.
my_class2
My class 1 docs.
my_class2
My class 1 docs.
my_class2
My class 1 docs.
my_class2
My class 1 docs.
my_class2
My class 1 docs.
my_class2
My class 1 docs.
my_class2
My class 1 docs.
my_class2
My class 1 docs.
my_class2
My class 1 docs.
my_class2
My class 1 docs.
my_class2
My class 1 docs.
my_class2
My class 1 docs.
my_class2
My class 1 docs.
my_class2
My class 1 docs.
my_class2
My class 1 docs.
my_class2
My class 1 docs.
my_class2
My class 1 docs.
my_class2
My class 1 docs.
my_class2
My class 1 docs.
my_class2
My class 1 docs.
my_class2
My class 1 docs.
my_class2
My class 1 docs.
my_class2
My class 1 docs.
my_class2
My class 1 docs.
my_class2
My class 1 docs.
my_class2
My class 1 docs.
my_class2
My class 1 docs.
my_class2
My class 1 docs.
my_class2
My class 1 docs.
my_class2
My class 1 docs.
my_class2
My class 1 docs.
my_class2
My class 1 docs.
my_class2
My class 1 docs.
my_class2
My class 1 docs.
my_class2
My class 1 docs.
my_class2
My class 1 docs.
my_class2
My class 1 docs.
my_class2
My class 1 docs.
my_class2
My class 1 docs.

我应该使用什么来打印所有方法文档字符串？

Answer 1

这是一个大量使用检查模块的解决方案。请注意，此深度仅2层。它不会捕获嵌套在其他类方法内的方法。我在相当多的随附软件包中对其进行了测试，并取得了良好的效果。

import inspect


def is_relevant(obj):
    """Filter for the inspector to filter out non user defined functions/classes"""
    if hasattr(obj, '__name__') and obj.__name__ == 'type':
        return False
    if inspect.isfunction(obj) or inspect.isclass(obj) or inspect.ismethod(obj):
        return True


def print_docs(module):
    default = 'No doc string provided' # Default if there is no docstring, can be removed if you want
    flag = True

    for child in inspect.getmembers(module, is_relevant):
        if not flag: print('\n\n\n')
        flag = False # To avoid the newlines at top of output
        doc = inspect.getdoc(child[1])
        if not doc:
            doc = default
        print(child[0], doc, sep = '\n')

        if inspect.isclass(child[1]):
            for grandchild in inspect.getmembers(child[1], is_relevant):
                doc = inspect.getdoc(grandchild[1])
                if doc:
                    doc = doc.replace('\n', '\n    ')
                else:
                    doc = default 
                print('\n    ' + grandchild[0], doc, sep = '\n    ')


import your_module
print_docs(your_module)

打印所有Class方法的python文档字符串

1 个答案: