Question

我正在尝试将套接字分配给特定用户的ID，并且似乎卡住了，例如，我有以下代码，

let user_list = {}

let socket = {}
socket[456] = "I am a socket"

user_list[123] = {...user_list, socket }
console.log(user_list)

我正在尝试获得以下结果：

{
  "123": {
    "456": "I am a socket"
  }
}

Answer 1

只需将散布运算符与socket对象一起使用：

let user_list = {}

let socket = {}
socket[456] = "I am a socket"

user_list[123] = {...user_list, ...socket}
console.log(user_list)

Answer 2

您不必为其本身分配<table id="example1" class="table table-bordered table-responsive"> <thead> <tr> <th>Id</th> <th>Producto</th> <th>Precio</th> </tr> </thead> <tbody> <tr> <td>@Html.DisplayFor(model => model.Id)</td> <td>@Html.DisplayFor(model => model.Nombre)</td> <td>@Html.DisplayFor(model => model.Precio) </td> </tr> </table>，请参见以下更改：

user_list

动态命名顶级对象键

2 个答案: