Question

我必须将此C代码转换为Mips，然后在Qtspim上运行代码

#include <stdio.h>
#include <stdlib.h>
#include <math.h>

int main(void) {
    int sum = 0;
    int i;
    for(i=0; i < 1000; i++)
    sum = sum + i;
    printf("sum=%d", sum);

    return 0;

}

我的Mips代码是

.data

.text

li $s1, 0
li $s2, 0
Loop:
    slt $t0, $s2, 1000
    beq $t0, $0, Exit
    add $s2, $s2, $s1
    addi $s1, $s1, 1
    j Loop
Exit:


li $v0, 1
move $a0, $s2

请告诉我怎么了。

说“试图在0x00400024处执行非指令

Answer 1

let colors = [
    ['#000','#00F','#0F0'],
    ['#0FF','#F00','#F0F'],
    ['#FF0','#FFF','#000']
]

let canvas_div = document.getElementById('canvas_div');
canvas_div.style.position = "fixed";
canvas_div.style.top = "50%";
canvas_div.style.left = "50%";
canvas_div.style.width = "0";
canvas_div.style.height = "0%";
canvas_div.style.transform = "scale(10) translate(-20px,-20px)";

for (i = 0; i < 3; i++){
    for (j = 0; j < 3; j++){
    let canvas = document.createElement('canvas');
    canvas.width = 100;
    canvas.height = 100;
    canvas.style.position = "fixed";
    canvas.style.top = `${i * 10}px`;
    canvas.style.left = `${j * 10}px`;
    canvas.style.width = "10px"
    canvas.style.height = "10px"
    let context = canvas.getContext("2d");
    context.fillStyle = colors[i][j];
    context.fillRect(-0,0,100,100);
        canvas_div.appendChild(canvas);
    }
}

尝试在0x00400024执行非指令。 Qtspim中的错误代码

1 个答案: