Question

我创建了一个小游戏（目前正在开发中）。我要在屏幕上打印出字典键的位置，并在按空格键后传递到下一个单词。但是，当我完成所有按键的迭代操作并按Q键退出游戏时，它没有任何作用。

这是我的代码：

import sys 
pygame.init() 
pygame.font.init() 

keywords  = {

            'auto': 'gives a local variable a local lifetime',
            'break': 'exits out of a compound statement',
            'case': 'a branch in a switch-statement',
            'char': 'a character data type',
            'const': 'makes a variable unmodifiable',
            'continue': 'continues to the top of a loop',
            'default': 'default branch in a switch-statement',
            'do': 'starts a do-while loop',
            'double': 'a double floating-point data type',
            'else': 'an else branch of an if-statement',
            'enum': 'defines a set of int constants',
            'extern': 'declares an identifier is defined externally',
            'float': 'a floating-point data type',
            'for': 'starts a for loop',
            'goto': 'jumps to a label',
            'if': 'starts an if statement',
            'int': 'an integer data type',
            'long': 'a long integer data type',
            'register': 'declares a variable be stored in a CPU register',
            'return': 'returns from a function',
            'short': 'a short integer data type',
            'signed': 'a signed modifier for integer data types',
            'sizeof': 'determines the size of the data',
            'static': 'preserves variable value after its scope exits',
            'struct': 'combine variables into a single record',
            'switch': 'starts a switch-statement',
            'typedef': 'creates a new type',
            'union': 'starts an union-statement',
            'unsigned': 'an unsigned modifier for integer data types',
            'void': 'declares a data type empty',
            'volatile': 'declares a variable might be modified elsewhere',
            'while': 'starts a while loop'

}



counter  = 0

size = (500, 700) 
screen = pygame.display.set_mode(size)
myfont = pygame.font.SysFont("Comic Sans MS", 30) 

while True:

    for event in pygame.event.get():

        if event.type == pygame.K_q:
            sys.exit()

        if event.type == pygame.KEYDOWN:
            if event.key == pygame.K_SPACE:
                try: 
                    counter += 1 
                    list_keys = list(keywords.keys()) 
                    screen.fill((255,255,255))
                    keyword = myfont.render(list_keys[counter], False, (0,0,0))
                    screen.blit(keyword, (200, 350))

                except IndexError: 
                    end_of_game_text = myfont.render("end of flashcards", False,(0,0,0))
                    screen.blit(end_of_game_text, (175, 325))


    pygame.display.flip()

这与while循环内设置按键事件的位置有关吗？按下按键事件后是否必须去？

我正在使用python 2.7和Windows 10作为操作系统。

Answer 1

pygame.K_q不是偶数类型（请参见pygame.event.EventType，它是键，请参见（pygame.key）。
验证事件类型是否为pygame.KEYDOWN（或pygame.KEYUP），然后将event.key与 k 键（pygame.K_q）比较。例如：

while True:

    for event in pygame.event.get():

        if event.type == pygame.KEYDOWN:

            if event.key == pygame.K_q:
                sys.exit()

            elif event.key == pygame..K_SPACE:
                # [...]

按下键盘上的Q键无法完成游戏

1 个答案: