Question

我试图创建一个将拨动开关恢复到关闭状态的功能。我用开关打开或关闭灯，但是有一个按钮，如果按一下，我希望所有灯都关闭并且开关都转到“关闭” 如您所见，有4个开关和一个按钮可关闭所有设备。而且我想知道如何在HTML，CSS和JS之间进行通信

<label class="switch">
    <input type="checkbox" name="one" id="one">
    <span class="slider round">
    </span> </label>
<label class="switch">
    <input type="checkbox" name="two" id="two">
    <span class="slider round">
    </span> </label>
<label class="switch">
    <input type="checkbox" name="three" id="three">
    <span class="slider round">
    </span> </label>
<label class="switch">
    <input type="checkbox" name="four" id="four">
    <span class="slider round">
    </span> </label>
<br>
<input type="button" id="stop" value="Stop All" onclick="shutdown()"><br>

Answer 1

我在这里为您创建了一个示例应用程序。 https://codesandbox.io/embed/lucid-brook-q6qsq

想法是使用document.querySelectorAll并遍历所有复选框，然后取消选中它们。这是相关代码：

document.querySelector("#stop").addEventListener("click", () => {
  const switches = document.querySelectorAll(".switch input");
  for (let s of switches) {
    s.checked = false;
  }
});

Answer 2

我建议您查找querySelectorAll

window.addEventListener("load", function() {
  document.getElementById("stop").addEventListener("click", function() {
    [...document.querySelectorAll(".switch input[type=checkbox]")].forEach(function(chk) {
      chk.checked = false; // and perhaps add chk.onchange() if needed
    });
  });
});

.switch {
  position: relative;
  display: inline-block;
  width: 60px;
  height: 34px;
}


/* Hide default HTML checkbox */

.switch input {
  opacity: 0;
  width: 0;
  height: 0;
}


/* The slider */

.slider {
  position: absolute;
  cursor: pointer;
  top: 0;
  left: 0;
  right: 0;
  bottom: 0;
  background-color: #ccc;
  -webkit-transition: .4s;
  transition: .4s;
}

.slider:before {
  position: absolute;
  content: "";
  height: 26px;
  width: 26px;
  left: 4px;
  bottom: 4px;
  background-color: white;
  -webkit-transition: .4s;
  transition: .4s;
}

input:checked+.slider {
  background-color: #2196F3;
}

input:focus+.slider {
  box-shadow: 0 0 1px #2196F3;
}

input:checked+.slider:before {
  -webkit-transform: translateX(26px);
  -ms-transform: translateX(26px);
  transform: translateX(26px);
}


/* Rounded sliders */

.slider.round {
  border-radius: 34px;
}

.slider.round:before {
  border-radius: 50%;
}

<label class="switch">
    <input type="checkbox" name="one" id="one">
    <span class="slider round">
    </span> </label>
<label class="switch">
    <input type="checkbox" name="two" id="two">
    <span class="slider round">
    </span> </label>
<label class="switch">
    <input type="checkbox" name="three" id="three">
    <span class="slider round">
    </span> </label>
<label class="switch">
    <input type="checkbox" name="four" id="four">
    <span class="slider round">
    </span> </label>
<br>
<input type="button" id="stop" value="Stop All" /><br>

古代浏览器的替代代码

var chks = document.querySelectorAll(".switch input[type=checkbox]"); 
for (var i=0;i<chks.length;i++) chks[i].checked = false;

Answer 3

在JavaScript中，您将使用getElementsByClassName()方法。您必须为所有复选框添加一个类，或者可以使用getElementsByTagName()来定位复选框标签。

let switches = document.getElementsByClassName("checkboxClass");

然后使用JavaScript遍历类

for (let i = 0; i < switches.length; i++) {
  switches[i].checked = false;
}

这将全部关闭。您可以将其放在函数中，并在任何时候（onclick / onchange等）调用它

希望这会有所帮助，祝您好运！

拨动开关回到关闭

3 个答案: