Firestore（python）侦听器完成的脚本，而不是侦听更改

Question

我正在尝试在python上设置Firestore on_snapshot侦听器。 但是，当我运行该程序时，它无需执行任何操作即可结束运行，更不用说听了。

我想念什么？

我试图一次性读取即.get（），并且它起作用了，所以我知道这不是程序包/凭据问题。

import firebase_admin
from firebase_admin import credentials
from firebase_admin import firestore

cred = credentials.Certificate("serviceAccountKey.json")
firebase_admin.initialize_app(cred)

db = firestore.client()

doc_ref = db.collection(u'someCollection').document(u'someDoc')

def on_snapshot (doc_snapshot, changes, read_time):
    for doc in doc_snapshot:
        print(u'New doc data: {}'.format(doc.id))

doc_watch = doc_ref.on_snapshot(on_snapshot)

Answer 1

似乎您试图以脚本形式运行此代码，该脚本似乎在执行回调函数之前已终止。因此，请尝试使from django.apps import AppConfig class MyAppConfig(AppConfig): name = 'apps.myapp' def ready(self): try: import apps.myapp.signals # noqa F401 import apps.myapp.tasks except ImportError: pass 对象的寿命足够长。

例如，使用doc_watch：

sleep

别忘了在结尾处from time import sleep import firebase_admin from firebase_admin import credentials from firebase_admin import firestore cred = credentials.Certificate("serviceAccountKey.json") firebase_admin.initialize_app(cred) db = firestore.client() doc_ref = db.collection(u'someCollection').document(u'someDoc') def on_snapshot (doc_snapshot, changes, read_time): global count for doc in doc_snapshot: print(u'New doc data: {}'.format(doc.id)) doc_watch = doc_ref.on_snapshot(on_snapshot) sleep(3) doc_watch.unsubscribe() ;）。