我已经尝试过几次将数据从一个片段发送到另一个片段,但它永远无法正常工作。我已经使用了“ Intent”和“ Bundle”,但是没有任何效果。他们说使用BroadCast接收器,但是Internet上的信息很少。谁能给我一个例子吗?
答案 0 :(得分:0)
片段通信中没有intent
传递概念,片段仅接受arguments
。这是使用bundle
进行片段通信的简单示例:
YourReceiverFragment newFragment = new YourReceiverFragment();
Bundle args = new Bundle();
args.putString("key1", data1);
args.putString("key2", data1);
newFragment.setArguments(args);
然后从onCreateView()
内部的另一个(接收方)片段中获取它,例如:
String value1 = getArguments().getString("key1");
// and so on
但是,片段到片段通信的另一种好的做法是通过interfaces
使用Activity
,例如:
SenderFragment :
public class SenderFragment extends Fragment {
SenderFragmentListener mCommunication;
public SenderFragment() {}// Required empty public constructor
@Override
public void onAttach(Context context) {
super.onAttach(context);
mCommunication = (SenderFragmentListener) context;
}
@Override
public View onCreateView(LayoutInflater inflater, ViewGroup container,
Bundle savedInstanceState) {
View view = inflater.inflate(R.layout.fragment_sender, container, false);
Button button = (Button) view.findViewById(R.id.btn_sender);
// on click button
button.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {
mCommunication.messageFromSenderFragment("Hello Fragment i am Sender...");
}
});
return view;
}
//Interface for communication
public interface SenderFragmentListener {
void messageFromSenderFragment(String msg);
}
@Override
public void onDetach() {
super.onDetach();
mCommunication = null;
}
}
活动:
public class MainActivity extends AppCompatActivity implements
SenderFragment.SenderFragmentListener{
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
}
@Override
public void messageFromSenderFragment(String msg) {
FragmentManager manager = getSupportFragmentManager();
ReceiverFragment mReceiverFragment = (ReceiverFragment)manager.findFragmentById(R.id.frg_Receiver);
mReceiverFragment.youGotMsg(msg);
}
}
ReceiverFragment :
public class ReceiverFragment extends Fragment {
TextView tv_msg;
public ReceiverFragment(){} // Required empty public constructor
@Override
public View onCreateView(LayoutInflater inflater, ViewGroup container,
Bundle savedInstanceState) {
View view = inflater.inflate(R.layout.fragment_receiver, container, false);
tv_msg = (TextView) view.findViewById(R.id.tv_receiver);
return view;
}
//Receive message
public void youGotMsg(String msg) {
tv_msg.setText(msg);
}
}
让我知道是否有帮助。
答案 1 :(得分:0)
除非使用视图模型,否则片段不会直接通信。这是一个指南,可以帮助您开始使用片段
https://github.com/codepath/android_guides/wiki/Creating-and-Using-Fragments
答案 2 :(得分:0)
您可以使用viewmodel在片段之间共享数据,可以在repo中查看详细信息: enter link description here
答案 3 :(得分:0)
可以使用捆绑软件在片段之间传递数据
您必须在尝试更改片段的地方写上这个
Bundle bundle = new Bundle();
bundle.putInt("key_name1", value1);
bundle.putString("key_name2", value2);
FragmentB fragmentB = new FragmentB();
fragmentB.setArguments(bundle);
在FragmentB中,您可以接收此数据(您可以在片段的onViewCreated()生命周期中编写此数据):
Bundle bundle = this.getArguments();
if (bundle != null) {
value1=bundle.getInt("key_name1", 0); //0 is the default value , you can change that
value2=bundle.getString("key_name2","");
}